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MrRa [10]
3 years ago
12

Find the solution of the differential equation that satisfies the given initial condition. du/dt = (2t+sec^2t)/2u, u(0) = -3

Mathematics
1 answer:
BabaBlast [244]3 years ago
5 0
Consider, pls, this option (see the attachment) of 3 steps.

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Solve for m: <br> 8(m + 2) = 3(12 - 4m)
Tema [17]

Answer:

m=1

Step-by-step explanation:

step 1: 8(m + 2) = 3(12 - 4m) remove the parentheses

step 2: 8 m + 2 = 3 12 - 4m move the terms

step 3: 8m+ 12m= 36 - 16 collect like terms and calulate

step 4: 20m=20 divide both sides

solution: m=1

3 0
3 years ago
Read 2 more answers
What is the value of x? Enter your answer in the box.<br><br> x= __
RoseWind [281]

Answer:

x =20

Step-by-step explanation:

We can use similar triangles and proportions to solve.  Take the smaller triangle side on top and the larger triangle side on the bottom.

11                 10

---------- = --------------

11+121             10 +5x+10

Combine like terms

11                 10

---------- = --------------

132             5x+20

Using cross products

11*(5x+20) = 10*132

55x+220 = 1320

Subtract 220 from each side

55x+220-220 = 1320-220

55x = 1100

Divide by 55

55x/55= 1100/55

x =20

8 0
4 years ago
What would be the answer to this question? I cannot figure it out.
hodyreva [135]

Answer:

Step-by-step explanation:

64 s^{12} - 125 y^{30} = 2^{6} s^{12} - 5³ y^{30} = ( 2² s^{4} )³ - ( 5 y^{10} )³ = ( 4 s^{4} )³ - ( 5 y^{10} )³

3 0
3 years ago
J has coordinates of (10,-2) and N has Coordinates of (-4,6). Find the midpoint of JN.
Thepotemich [5.8K]

Midpoint of JN is at coordinates (3,2)

Step-by-step explanation:

Coordinates of j= (10,-2)

Coordinates of N = (-4,6)

We need to find midpoint of JN.

The formula used to find midpoint is:

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given:

x_1=10,x_2=-4,y_1=-2,y_2=6

Putting values and finding midpoint of JN

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Midpoint=(\frac{10-4}{2},\frac{-2+6}{2})

Midpoint=(\frac{6}{2},\frac{4}{2})

Midpoint=(3,2)

So, midpoint of JN is at coordinates (3,2)

Keywords: Midpoint of line

Learn more about Midpoint of line at:

  • brainly.com/question/3269852
  • brainly.com/question/1473992
  • brainly.com/question/909890

#learnwithBrainly

8 0
4 years ago
17x2 + 7x - 14<br> This algebra 1
Anika [276]

Answer:

x = 2.857 [rounded]

Step-by-step explanation:

17 x 2 = 34.

Next, we combine.

34 - 14 = 20.

Lastly, we divide 20 by 7.

20 / 7 = 2.857

<em>[The answer </em><em>is</em><em> </em><em>a</em><em> </em><em>decimal</em><em> </em><em>that</em><em> </em><em>doesn't</em><em> </em><em>end</em><em>,</em><em> </em><em>but</em><em> </em><em>I</em><em> </em><em>rounded</em><em> </em><em>it</em><em> </em><em>for</em><em> </em><em>simplicity</em><em>.</em><em>]</em>

4 0
3 years ago
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