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rewona [7]
3 years ago
12

Triangle STU is located at S (2, 1), T (2, 3), and U (0, −1). The triangle is then transformed using the rule (x−4, y+3) to form

the image S'T'U'. What are the new coordinates of S', T', and U'? (10 points)
Mathematics
2 answers:
sp2606 [1]3 years ago
4 0
Triangle STU is located at : S(2,1) , T(2,3) and U(0,-1)

transformation rule : (x - 4, y + 3)

so S' is : (2 - 4 , 1 + 3) = (-2,4) <==
and T' is : (2 - 4, 3 + 3) = (-2,6) <==
and U' is : (0 - 4, -1 + 3) = (-4,2) <==
Nat2105 [25]3 years ago
3 0

Answer:  The new vertices are S'(-2, 4), T'(-2, 6) and U'(-4, 2).

Step-by-step explanation:  Given that the triangle STU is located at S(2, 1), T(2, 3), and U(0, −1). Triangle STU is then transformed using the rule (x−4, y+3) to form the image S'T'U'.

We are to find the new co-ordinates of S', T' and U'.

To find the new co-ordinates of S', T' and U', we should subtract 4 from x co-ordinate of each vertex and should add 3 to the y co-ordinate of each vertex.

The new vertices after the transformation are as follows :

S(2, 1)   ⇒   S'(2-4, 1+3) = S'(-2, 4)

T(2, 3)  ⇒   T'(2-4, 3+3) = T'(-2, 6)

and

U(0, -1) ⇒  U'(0-4, -1+3) = U'(-4, 2).

Thus, the new vertices are S'(-2, 4), T'(-2, 6) and U'(-4, 2).

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