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erastovalidia [21]
3 years ago
9

WILL MARK BRANLIEST

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

0.47metres per minute

Step-by-step explanation:

you would minus t 5 from 3 which would be 1.34- 0.87 which equals 0.47

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A central angle of a circle measures 1.5 radians. If the radius of the circle is 3 cm, what is the area of the related sector?
soldi70 [24.7K]

Answer:

Option B. 6.75\ cm^{2}

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^{2}

we have

r=3\ cm

substitute

A=\pi (3^{2})=9 \pi\ cm^{2}

Remember that

2\pi radians subtends the complete circle of area 9 \pi\ cm^{2}

so

by proportion

Find the area of the related sector for a central angle of 1.5 radians

Let

x------> the area of the related sector

\frac{9 \pi}{2\pi}\frac{cm^{2}}{radians} =\frac{x}{1.5}\frac{cm^{2}}{radians}\\ \\x=9*1.5/2\\ \\x= 6.75\ cm^{2}

7 0
3 years ago
Im not understanding this question
natita [175]

It's said "The value √-9 is not -3 because --------------------

So you need to prove why -3 is not the value of √-9.


As you know (-3)^2 = (-3) * (-3) = 9, ≠ -9


Answer is A. 

(-3)^2 ≠ -9

7 0
3 years ago
Read 2 more answers
You have 35 yards of ribbon for your gift boxes. Each box gets the same amount of ribbon. How much ribbon will each of your 30 g
Lubov Fominskaja [6]
1.16 of a yard, don’t know if this is correct but worth a shot
6 0
3 years ago
Read 2 more answers
Plzz help <br><br>find value of following : 2sin75°.cos15°​
polet [3.4K]

Answer:

\frac{2+\sqrt{3} }{2}

Step-by-step explanation:

Using the product to sum formula

sinxcosy = \frac{1}{2} [ sin(x + y) + sin(x - y) ] , then

2sinxcosy = sin(x + y) + sin(x - y)

Given

2sin75°cos15° ← with x = 75 and y = 15 , then

= sin(75 + 15) + sin(75 - 15)

= sin90° + sin60°

= 1 + \frac{\sqrt{3} }{2}

= \frac{2+\sqrt{3} }{2}

6 0
3 years ago
Please help I’m lost it has to be 3 or 2 or more answers by the way and I will except answers from Expert, Ace, or Genius or any
deff fn [24]
The correct answer is only A, because you need the tenths place to be greater than the number on the left, and not just the hundredths place.

P.S. Even though I'm a beginner, I took Multi-Variable calculus in 12th grade.
P.P.S. STOP PUTTING ON RANDOM ANSWERS ON QUESTIONS JUST SO YOU CAN GET THE POINTS!!!!!! 
4 0
3 years ago
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