3 years ago

The perimeter of an equilateral triangle is at most 45centimeters. Find the possible length of each side.

Mathematics

1 answer:

MAXImum [283]3 years ago

4 0

Imdomt really understand but i done 180 divide 3 = 60

You might be interested in

Find the distance between the points: (1,2) and (-3,0)

faltersainse [42]

You can create a right angled triangle.
Find the hypotenuse.
The third point of the triangle is (1,0)
using pythagoras, the value of a is 2, b is 3. 2^2 +3^2 = 13.
Therefore the distance between the two points is $\sqrt{13}$

7 0

3 years ago

The level of college education and wages earned are known to have a strong positive association. Karen concluded that a college

vazorg [7]

Answer:

Karen's conclusion is not valid because association does not imply causation.

Step-by-step explanation:

4 0

3 years ago

180 red marbles to 145 blue marbles <br> ratio

Ket [755]

Answer:

36 : 29

Step-by-step explanation:

Require to simplify the ratio

180 : 145

Divide both parts by 5

= 36 : 29 ← in simplest form

Simplest form means that no other number but 1 will divide into the 2 parts of the ratio.

6 0

3 years ago

Olivia deposit 6952 in a savings account paying 3.72% interest to the nearest dollar how much money does Olivia have in total af

lianna [129]

Pretty sure 11,090!............................

4 0

3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

4 0

3 years ago