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Ann [662]
3 years ago
15

The perimeter of an equilateral triangle is at most 45centimeters. Find the possible length of each side.

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0
Imdomt really understand but i done 180 divide 3 = 60
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Find the distance between the points: (1,2) and (-3,0)
faltersainse [42]
You can create a right angled triangle.
Find the hypotenuse.
The third point of the triangle is (1,0)
using pythagoras, the value of a is 2, b is 3. 2^2 +3^2 = 13.
Therefore the distance between the two points is \sqrt{13}
7 0
3 years ago
The level of college education and wages earned are known to have a strong positive association. Karen concluded that a college
vazorg [7]

Answer:

Karen's conclusion is not valid because association does not imply causation.

Step-by-step explanation:

4 0
3 years ago
180 red marbles to 145 blue marbles <br> ratio
Ket [755]

Answer:

36 : 29

Step-by-step explanation:

Require to simplify the ratio

180 : 145

Divide both parts by 5

= 36 : 29 ← in simplest form

Simplest form means that no other number but 1 will divide into the 2 parts of the ratio.

6 0
3 years ago
Olivia deposit 6952 in a savings account paying 3.72% interest to the nearest dollar how much money does Olivia have in total af
lianna [129]
Pretty sure 11,090!............................
4 0
3 years ago
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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