Question

Kevin has a spinner that has 10 equal sections and 2 sections of each color—red, blue, green, yellow, and purple. Kevin spins the spinner 180 times. Kevin determines about how many times the spinner will land on red or green, and his work is shown below. P (red or green) = StartFraction Number of red or green sections over Total number of sections EndFraction times number of spins = StartFraction 2 over 10 EndFraction (180) = 36. What mistake did Kevin make, if any?

Answer 1

Answer:

The mistake in Kevin's calculation is when calculating P(Red or Green).

Step-by-step explanation:

Given

$Sections = 10$

$Spins = 180$

$Red, Blue, Green, Yellow, Purple = 2\ each$

Required

Spot the mistake in Kevin's calculation

From the question, we have that:

Kevin's calculation

$P(Red\ or\ Green) = \frac{2}{10}$

Number of times;

$Times = \frac{2}{10} *180 = 36$

The mistake in Kevin's calculation is when calculating P(Red or Green).

$P(Red\ or\ Green) = \frac{Number\ of\ red\ or\ green}{Total}$

He considered only one section instead of both sections

The correction is:

Since, there are 2 green sections and 2 red sections.

The equation becomes

$P(Red\ or\ Green) = \frac{2 + 2}{10}$

$P(Red\ or\ Green) = \frac{4}{10}$

And the number of times is:

$Times = \frac{4}{10} * 180$

$Times = \frac{720}{10}$

$Times = 72$

Answer 2

Answer:

The answer would be: The mistake in Kevin's calculation is when calculating P(Red or Green).

Step-by-step explanation:

c: