the amount of gold present is - 9/10 of an ounce of gold
from this gold they have to split into groups of 1/6 ounce each
so we have to divide 9/10 ounce in to groups of 1/6
for this we have to divide 9/10 by 1/6
when dividing fractions we mutiply the first fraction by the reciprocal of the second fraction
reciprocal of 1/6 is - 6/1
so the number of groups that can be made is 5 whole groups with 0.4 ounce of gold remaining
the whole number of groups that can be made - 5
L = 
- W
P = 2L + 2W = 2(L + W) → ( take out common factor of 2)
divide both sides by 2
= L + W
subtract W from both sides
- W = L
Answer:
1) the quadrants go counter clockwise, Quadrant I is the upper right square, Quadrant II is the upper left square, Quadrant III is the lower left square, and Quadrant IV is the lower right square.
2) Quadrant II
3) Quadrant IV
4) Quadrant III
5) Quadrant I
6) Both would be on the horizontal axis
7) Both would be on the vertical axis
Step-by-step explanation:
Hope this helped!
Answer:
-24n + 42
Step-by-step explanation:
(7 - 4n) · 6
Apply distribute property.
7 · 6 - 4n · 6
42 - 24n
