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nasty-shy [4]
3 years ago
9

Given that abc and def are similar find fd

Mathematics
1 answer:
hjlf3 years ago
4 0

Answer:

FD = 8

Step-by-step explanation:

since they are similar triangle .use these ratios to find FD

AB/DE = AC/FD

now substitute the values

6/x-3 = 12/x+1

do cross multiplication

12(x-3) = 6(x+1)

12x - 36 = 6x + 6

12x - 6x = 6 + 36

6x = 42

x = 42/6

x = 7

now substitute x

FD = x + 1

=7 + 1

=8

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lana [24]

Answer: D and E I'm sure

3 0
3 years ago
Please help me (please dont send links)
Burka [1]

Answer:

Part A

79.4

Part B

84

Part C

The science class

Step-by-step explanation:

The linear function representing the average test score in the math class, after taking <em>x</em> number of tests, f(x) = 0.2·x + 79

The science class average test score, after taking <em>x</em> number of tests, is given by the linear function g(x)

The values of g(x) are presented as follows;

x; 1, 2, 3

g(x); 86, 84, 82

Part A

By using the given function for the test average for the math class, f(x), when x = 2, we have;

f(2) = 0.2 × 2 + 79 = 79.4

The test average for the math class after completing test 2 = 79.4

Part B

The test average for the science class after completing test 2 from the table is 84

Part C

After completing test 4, the test average for the math class, f(4), is given as follows;

f(4) = 0.2 × 4 + 79 = 79.8

The test average for the science class after the completing test 4 is found by noting that the test average, g(x) decreases by 2 for each increase in the number of test taken, <em>x</em>, by 1

Given that the test average of the science, g(3) class after taking test 3 is 82, the test average after taking test 4, g(4) = g(3) - 2 = 82 - 2 = 80

g(4) = 80

Therefore, after completing test (4), the science class has a higher test average g(4) = 80, than the math class f(x) = 79.8

3 0
3 years ago
Trevor and $826 on account during 2.5% annual interest for seven years.
photoshop1234 [79]

Trevor invested $ 4720

<em><u>Solution:</u></em>

Given that, Trevor earned $ 826 on account during 2.5% annual interest for seven years

We can simple interest formula

<em><u>The formula for simple interest is given as:</u></em>

\text{ Simple Interest } = \frac{p \times n \times r}{100}

Where,

"p" is the principal

"n" is the number of years

"r" is the rate of interest

Here given that,

Principal = p = ?

rate of interest = r = 2.5 %

number of years = n = 7

Simple interest earned = 826

<em><u>Substituting the values in above formula,</u></em>

826 = \frac{p \times 7 \times 2.5}{100}\\\\82600 = p \times 7 \times 2.5\\\\82600 = 17.5p\\\\p = \frac{82600}{17.5}\\\\p = 4720

Thus he invested $ 4720

7 0
3 years ago
Is 3 to the negative 1 power times 3 to the negative 1 power equal to 3 to the 1 power?
iren2701 [21]
To make the exponent positive, make a fraction. 1/3 * 1/3. This is 0.1 repeating. 3^1 is 3. So the answer is no.
3 0
4 years ago
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