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ANEK [815]
3 years ago
15

Please help me out!!

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0
Can do.

Arc length = radius * theta.
S=r*theta

Convert 73° to radians.
(73°)*(pi/180)
73°=1.274rad


S=(6.48in.)(1.274rad) = 8.255 in = final answer
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Find the missing side of the angle.<br> Need help, thank you!!
Alex787 [66]

Answer:

sqrt239

Step-by-step explanation:

Using the pythagoream thereom, we know that a^2+b^2=c^2.

so x^2+17=256

That makes x the square root of 239.

4 0
2 years ago
What is the number of the variable X?​
Olenka [21]

Answer:

\huge\boxed{x = -18}

Step-by-step explanation:

\frac{x-3}{3} = \frac{2x+1}{5} \\\\Cross \ Multiplying\\\\3(2x+1) = 5(x-3) \\\\Resolving \ Parenthesis\\\\6x+3 = 5x-15\\\\Combining \ like \ terms\\\\6x-5x = -15-3\\\\\bold{x = -18}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
3 years ago
Subtract 3x + 2 from 8x + 9.​
kirill115 [55]

Answer:

5x+7

Step-by-step explanation:

Subtract like terms

(8x+9)-(3x+2)

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5x+7 should be your answer I believe

3 0
3 years ago
If CE bisects ZBCD and if m ZBCE = 3x - 6
horrorfan [7]

Answer:

m∠BCD = 90°

∠BCD is a right angle

Step-by-step explanation:

<em>If a ray bisects an angle, that means it divides the angle into two equal parts in measure</em>

∵ Ray CE bisects ∠BCD

→ Means divide it into two angles BCE and ECD which equal in measures

∴ m∠BCE = m∠ECD = \frac{1}{2} m∠BCD

∵ m∠BCE = 3x - 6

∵ m∠ECD = 2x + 11

→ Equate them to find x

∴ 3x - 6 = 2x + 11

→ Add 6 to both sides

∵ 3x - 6 + 6 = 2x + 11 + 6

∴ 3x = 2x + 17

→ Subtract 2x from both sides

∵ 3x - 2x = 2x - 2x + 17

∴ x = 17

∵ m∠BCE =  \frac{1}{2} m∠BCD

→ Substitute x in the measure of ∠BCE to find it, then use it to

   find m∠BCD

∵ m∠BCE = 3(17) - 6 = 51 - 6

∴  m∠BCE = 45°

∵ 45 = \frac{1}{2} m∠BCD

→ Multiply both sides by 2

∴ 90 = m∠BCD

∴ m∠BCD = 90°

→ The measure of the acute angle is less than 90°, the measure of

   the obtuse angle is greater than 90°, and the measure of the

   right angle is 90°

∴ ∠BCD is a right angle

6 0
3 years ago
-1 3/5 ÷-2/3 as a mixed number​
SCORPION-xisa [38]

\text{Hey there!}

-1\frac{3}{5}\div\frac{2}{3}

-1\frac{3}{5}=-\frac{8}{5}

\text{Problem becomes:}-\frac{8}{2}\div\frac{2}{3}

\text{Solve that, and you will get:}\frac{-4}{5}\div{\frac{3}{1}}

-4\times1=-4

5\times3=15

\rightarrow =\frac{-4}{15}

\boxed{\boxed{\boxed{\bf{Answer:\frac{-4}{15}}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

6 0
3 years ago
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