An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha
t is the horizontal distance before they fly over it?
1 answer:
Answer:
11196.15 km
Step-by-step explanation:
Consider the attached diagram
If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.
Using trigonometry
Cross multiply
|AB|X Tan 15 =3000
|AB| = =11196.15 km
Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km
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Answer:
First: 15
Second: 21
Third: 45
Step-by-step explanation:
In order to create the equation we need to represent the evenings with an alebraic term, in thsi case we are going to represent the second evening with an X
Second evening:x
The first night she got 6 fewer calls than the second: Second-6=x-6
The third night she received 3 times the first: 3(first night)=3(x-6)
The equation is First Night plus second night plus third night equals 81.
So the first evening he received 15 calls, the second he received 21 and the third one he received 45.