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victus00 [196]
3 years ago
7

Javier works in a photo lab and needs to make a reduced copy of a photograph that is 8 inches long. The customer wants the copy

to have a length of 4.5 inches. Each time he presses the reduce button on the copier, the copy is reduced by 12%. Javier and his boss had an argument, because Javier claimed that pressing the button 5 times would be enough to fulfill the customer's request. His boss said that pressing the button 5 times would result in a length less than the desired 4.5 inches. Which of the following conclusions can be made?
Mathematics
2 answers:
Delvig [45]3 years ago
7 0

The correct answer is

<u>D. Javier's boss is correct and he should not press the button five times.</u>

<u></u>

Novay_Z [31]3 years ago
6 0
To find the percentage that the customer wants reduced, we use this equation:
8n = 4.5
n = 4.5/8
n = 0.5626
Because javier believes that reducing 12% 5 times would work, he is assuming that:
56.26 - 60 = 0
This is not the case.
Javier's boss is correct.
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For f(x)=4x+1 and g(x)=x^2-5,find(f•g)(4)
RoseWind [281]

Answer:

(f•g)(4) = 45

Step-by-step explanation:

f(x)=4x+1

g(x)=x^2-5

(f•g)(x) = 4(x^2 -5)+1

(f•g)(4) = 4(4^2 -5)+1

(f•g)(4) = 4(16-5)+1

(f•g)(4) = 4(11)+1

(f•g)(4) = 44 + 1

(f•g)(4) = 45

8 0
3 years ago
Read 2 more answers
Identify the slope and y-intercept for each equation below.<br> y=2x-5
sammy [17]

Answer:

Slope=2

y-intercept=-5

Step-by-step explanation:

This equation is in the form of y=mx+b

m is the slope and b is the y-intercept.

Therefore, the slope is 2 and the y-intercept is -5

5 0
3 years ago
Read 2 more answers
Pre college need help
AVprozaik [17]

Answer:

sorry I can't answer that because I need points very3× sorry

3 0
3 years ago
PLEASE HELP ME WITH THIS ASAP! please and thank you
Mice21 [21]

<em>Answer,</em>

<em><u>5</u></em>

<em>Explanation,</em>

<em><u>Simply input the numbers in the equation & solve.</u></em>

<em>(12)(3) − 3(1/3)</em><em>/</em><em>(4)(3) − 5</em>

<em>= 36 − 3(1</em><em>/</em><em>3)</em><em>/</em><em>(4)(3) − 5 </em>

<em>= 36 − 1</em><em>/</em><em>(4)(3) − 5 </em>

<em>= 35</em><em>/</em><em>(4)(3) − 5 </em>

<em>= 35</em><em>/</em><em>12 − 5 </em>

<em>= 35</em><em>/</em><em>7</em>

<em><u>= 5</u></em>


<u><em>Hope This Helps :-)</em></u>


7 0
3 years ago
Read 2 more answers
A sample of Iron-59 contains 50 mg. One hundred days later, the sample contains 10.75 mg. What is the half-life of iron-59, in d
exis [7]

Answer:

t_{1/2}=45.09 d    

Step-by-step explanation:

We can use the decay equation:

M=M_{0}e^{-\lambda t}

  • M(0) is the initial mass
  • M is the mass after t (1000 days) time
  • λ is the decay constant

But:

\lambda = ln(2)/t_{1/2}

  • t(1/2) is the half-life.

So, we can rewrite the initial equation:

M=M_{0}e^{-\frac{ln(2)}{t_{1/2}}t}

Now, we just need to solve it for t(1/2):

ln(\frac{M}{M_{0}})=-\frac{ln(2)}{t_{1/2}}t

t_{1/2}=-\frac{ln(2)}{ln(\frac{M}{M_{0}})}t

t_{1/2}=-\frac{ln(2)}{ln(\frac{10.75}{50})}100                

t_{1/2}=45.09 d    

I hope it helps you!

5 0
3 years ago
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