Question

Two cars leave simultaneously from points A and B, the distance between which is 280 km. If the cars move to meet each other, they’ll meet in 2 hours. But if they move in the same direction, then the car going from point A will catch up with the car going from point B in 14 hours. What is the speed of each of the cars?

Answer 1

V1 = 80 km/hr

v2 = 60 km/hr

The speed of the car from point A is 80 km/hr while the speed of the car from point B is 60 km/hr.

Hope This Helps!

Answer 2

Answer:

Speed of Car A is 80 km/h   and speed of Car B is 60 km/h.

Step-by-step explanation:

let v1 be speed of car A and v2 be speed of car B.

Then According to Question,

If they move in the same direction, then Car A will travel an ( x + 280 ) km while Car B will travel an x km. They both cover this in 14 hr.

using speed distance formula, we get

v1 × 14 = x + 280  

v2 × 14 = x  

$v1=\frac{x}{14}+\frac{280}{14}=\frac{x}{14}+20$  

$v2=\frac{x}{14}$  

v1 = v2 + 20 .................(1)

Moving towards each other, they'll collectively cover 280 km in 2 hours.

2 × (v1 + v2) = 280  

2 × (v2 + 20 + v2) = 280   (from eqn (1))  

v2 + v2 + 20 = 140  

2 × v2 = 120  

v2 = 60  

v1 = 60 + 20 = 80  

Therefore, Speed of Car A is 80 km/h   and speed of Car B is 60 km/h.