Question

Mrs. Piper is driving Anna, Jo, and Mai home from school. All of them want to ride in the front seat. How can she make a fair decision about who rides in the front seat?

Answer 1

Answer:

A and B

Step-by-step explanation:

Randomly selecting the kid will be a fair decision.

A. True because all kids have the same percentage to win

The probability that Anna wins: 1/6 + 1/6 = 1/3

The probability that Jo wins: 1/6 + 1/6 = 1/3

The probability that Mai wins: 1/6 + 1/6 = 1/3  

B. True because all kids have the same percentage to win

The probability that Anna wins: 1/3

The probability that Jo wins: 1/3

The probability that Mai wins: 1/3

D. Wrong. Because all kids do not have the same percentage to win

No matter what the result is in the 1st toss, Mai always have 100% chance to move to the second toss. While Jo and Anna only have 50% to go to the second toss.

D. Wrong. Because all kids do not have the same percentage to win

The probability that Anna wins: 1/6

The probability that Jo wins: 1/6

The probability that Mai wins: 4/6 = 2/3

Answer 2

Answer:

option-B and option-A

Step-by-step explanation:

we will select each options and then we verify it

(A)

We know that when a die is rolled

There six possibilities

and two numbers are assigned to each

so, each are getting equal shares

so, this is fair

so, this is TRUE

(B)

There will be three names in three piece of paper

so, each having equal probability of getting front seat

so, this makes a fair decision

so, this is TRUE

(C)

We know that when a coin is flipped twice  , we can get same face again and again

It won't make equal probability for each one

so, it won't be fair for anyone

so, this is FALSE

(D)

We know that when a die is rolled , we can get same number again and again

It won't make equal probability for each one

so, it won't be fair for anyone

so, this is FALSE