Answer:
a=12
Step-by-step explanation:
Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Answer: 6x-3
Step-by-step explanation: Say that the third side is y. The equation for the perimiter is side 1+ side 2+ side 3= perimeter which if you intput what we have turns out like (10x+2) +(8x-1)+y=24x-2. If you add 10x+2 and 8x-1 you get 18x+1. We can update the previous equation making it (18x+1)+y=24x-2. Since your trying to find y, you isloate it by subtracting (18x+1) from both sides. This leaves us with y=6x-3 as the length of thr missing side.
Answer:
Factored form: 2x(2x^2+x+1)
Step-by-step explanation:
You're subtracting them. :)
<h2>25 </h2>
Step-by-step explanation:
<h3><em>=</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>(</em><em>5</em><em> </em><em>-</em><em> </em><em>1</em><em>)</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>1</em><em>2</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>2</em><em>5</em></h3>
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