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Ket [755]
2 years ago
10

Question is in the screenshot

Mathematics
1 answer:
sukhopar [10]2 years ago
7 0

Answer:

3/10

Step-by-step explanation:

Between 10 and 15 on the horizontal scale are 3 blue rectangles.  The total number of such rectangles is 10.  Thus, the probability of obtaining a number between 10 and 15 is 3/10.

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2/3 ..................

4 0
3 years ago
Help? also explain pls
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Answer:

158ft²

Step-by-step explanation:

Break it up!

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The diameter of an insect cell is 1.7 × 10–11 meter. Ariel wants to find the length of the radius of the cell. If she performs t
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6 0
2 years ago
Solve the equation. 12x – 15 = 3(2x +3)
MA_775_DIABLO [31]

Answer:

x = 4

Step-by-step explanation:

Solve for x:

12 x - 15 = 3 (2 x + 3)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

12 x - 15 = 6 x + 9

Hint: | Move terms with x to the left hand side.

Subtract 6 x from both sides:

(12 x - 6 x) - 15 = (6 x - 6 x) + 9

Hint: | Combine like terms in 12 x - 6 x.

12 x - 6 x = 6 x:

6 x - 15 = (6 x - 6 x) + 9

Hint: | Look for the difference of two identical terms.

6 x - 6 x = 0:

6 x - 15 = 9

Hint: | Isolate terms with x to the left hand side.

Add 15 to both sides:

6 x + (15 - 15) = 15 + 9

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

6 x = 9 + 15

Hint: | Evaluate 9 + 15.

9 + 15 = 24:

6 x = 24

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 6 x = 24 by 6:

(6 x)/6 = 24/6

Hint: | Any nonzero number divided by itself is one.

6/6 = 1:

x = 24/6

Hint: | Reduce 24/6 to lowest terms. Start by finding the GCD of 24 and 6.

The gcd of 24 and 6 is 6, so 24/6 = (6×4)/(6×1) = 6/6×4 = 4:

Answer:  x = 4

8 0
2 years ago
The equation with the restriction x, is on the terminal side of an angle in standard position.
marishachu [46]
4 because it hits the dextran quadran of the terminal side in a standered position while  also...

just imagin a triange with four on top and -2 on side

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3 years ago
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