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vovikov84 [41]
4 years ago
13

Does the equation 3(x-2)=3x-2 have one solution, no solution or an infinite number of solutions?

Mathematics
1 answer:
romanna [79]4 years ago
4 0

If you expand the left hand sign, the equation becomes

3x-6 = 3x-2

This means that the term 3x cancels out, since it appears in both sides. So, we're left with

-6=-2

which is clearly false, i.e. it leads to an impossible equation, which thus have no solutions.

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What value of b makes the equation true?<br> -6(b+3)=-8b+5
Dmitry_Shevchenko [17]
The answer is b= - 5/2

- 6 (b + 3)= - 8 + 5

- 6b - 18= - 3

- 6b= - 3 + 18

- 6b= 15

b= - 15/6

b= - 5/2
6 0
4 years ago
Read 2 more answers
1.) Find all the factors of 54.
jonny [76]

QUESTION 1.

The factors of 54  are all natural numbers that can divide 54 exactly.

The factors of 54 are: {1,2,3,6,9,18,27,54}

QUESTION 2

The prime factors of 54 are factors of 54 that are prime numbers.

The prime factors of 54 are {2,3}.

Product of prime factors of 54 is 2\times 3^3

QUESTION 3

All the factors of 60 are all positive integers that divide exactly into 60.

The factors of 60 are {1,2,3,4,5,6,10,12,15,20,30,60}

QUESTION 4

The prime factors of 60 are factors of 60 that are prime numbers.

The prime factors of 60 are {2,3,5}

The prime factorization of 60 is 2^2\times 3\times 5.

QUESTION 5

The factors of 30 are {1,2,3,5,6,10,15,30}

The different ways she can put the beads into the boxes are

1\times 30,

All 30 beads into one box or 1 bead in 30 boxes.

2\times 15,

2 beads each into 15 boxes or 15 beads each into 2 boxes

3\times 10,

3 beads each into 10 boxes or 10 beads each into 3 boxes

5\times 6,

6 beads each into 5 boxes or 5 beads each into 6 boxes

5 0
4 years ago
What number is a number that is even and not even at the same time? And what are they divided in half?
Savatey [412]

Definitions:

A number, x, is even if it satisfies: x = 2n for some integer n

A number, x, is odd if it satisfies: x = 2k+1 for some integer k

Rewriting the Question:

In this case the question is asking if there is a number, x, that is has the following property:

x = 2n for some integer n AND x = 2k+1 for some integer k

Proof:

We can set these two equations equal:

2n = x = 2k + 1

2n = 2k + 1

2n - 2k = 1

2(n - k) = 1

Let number y = n - k. Note that since n and k are integers, n-k (and therefore, y) must also be an integer.

2y = 1

You can see on the left side (2y) that this becomes the definition of an even number! So the left side is an even number and the right side is 1. Since we know by definition that 1 is not an even number and k must be an integer (not 0.5), this equation becomes false.

As a result, there are NO numbers that can be both even AND odd.

8 0
3 years ago
1. Marina and Brian have a joint checking account. They have a balance of $3,839.25 in the
NNADVOKAT [17]
The 2nd one i think
7 0
4 years ago
Parker has $15 to order pizza. The plain cheese pizza costs $11.75, and each extra topping costs $1.25.
Vilka [71]

Parker can only add 2 extra toppings.

$11.75 + ($1.25 x 2) = $14.25.

Hope this helps! ^v^

5 0
3 years ago
Read 2 more answers
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