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zlopas [31]
3 years ago
6

Write an expression to find the difference in the maximum area and minimum area of nys high school soccer field. Then evaluate y

ou expression.
Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0
You didn't give the numbers but an expression is a problem with no equals so you do t pit the total if that helps at all
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130.47 - 108.17
22.3 percentage increase 
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Name two obtuse vertical angles
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HGE and FGD would be your answers
5 0
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PLEASE help me...Suck at math. find the following using the given triangle.
Ulleksa [173]
To find the perimeter just add the sides

5+5+6 = 16

To find the area, you need to use the following formula

area = \frac{1}{2}bh
we know b but we need to find the height. We can find the heigh by using pythagorean theorem a^2 + b^2 = c^2

height = a^2 + 3^2 = 5^2
             a^2 + 9 = 25
             a^2  = 25 - 9
             a^2 = 16 
            a = \sqrt{16} = 4 
            h = height = 4

area = \frac{1}{2}\times 6\times 4 = 12cm^2

Cost:

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4 0
3 years ago
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-3(x+3)^2-3+3x simplify in standard form
IrinaK [193]

Answer: −3x²​​−15x−30

Step-by-step explanation: use Square of Sum (a+b)²=a²+2ab+b²

−3(x²​​+2x×3+3²)-3+3x

−(3x²​​ +18x+27)−3+3x

−3x​​²−18x−27−3+3x

−​3x²+(−18x+3x)+(−27−3)

−3x²​​−15x−30

Hope this helps, now you know the answer and how to do it. Stay healthy and safe and HAVE A BLESSED AND WONDERFUL DAY! :-)

- Cutiepatutie ☺❀❤

6 0
3 years ago
1. Consider the function f(x) = 5x^3 - 31x^2 - 129x + 27
NeX [460]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

1.- f(x) = 5x³ - 31x² - 129x + 27

a) f(9) = 5(9)³ - 31(9)² - 129(9) + 27

   f(9) = 5(729) - 31(81) - 1161 + 27

   f(9) = 3645 - 2511 - 1161 + 27

   f(9) = 0

b.- I will use synthetic division

                        5   - 31  -129  + 27       9

                               45   126  -27                            

                        5     14     -3       0

    Trinomial = 5x² + 14x - 3

Factor               5x² + 15x - 1x - 3

                        5x(x + 3) - 1(x + 3)

b)                           (x + 3)(5x - 1)

                       x₂ + 3 = 0          5x₃ - 1 = 0

                       x₂ = -3                 x₃ = 1/5

c) The roots are x₁ = 9, x₂ = -3 and x₃ = 1/5

2.-  f(x) = 3x² + 2x - 8      factor = 3x - 4

                                     x    + 2

                       3x - 4    3x² + 2x - 8

                                   -3x² + 4x

                                     0    +6x - 8

                                           -6x  + 8

                                                      0  Remainder

As the remainder was "0", 3x - 4 is a factor of 3x² + 2x - 8

3 0
3 years ago
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