Boris's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Boris
1 answer:
X=pounds of Type A coffee y=pounds of Type B coffee QUANTITY EQUATION: x+y=178 COST EQUATION: $5.45x + $4.20y=$870.10 STEP 1: Solve for one variable in equation one. Then substitute it in equation two. x+y=178 subtract y from both sides of the equation x=178-y STEP 2: substitute x=178-y in equation two 5.45x + 4.20y=870.10 5.45(178-y) + 4.20y=870.10 multiply 5.45 by everything in parentheses (5.45*178)+(5.45*-y)+4.20y=870.10 970.10-5.45y+4.20y=870.10 combine like terms 970.10-1.25y=870.10 subtract 970.10 from both sides -1.25y=-100 divide both sides by -1.25 y=80 pounds of type B coffee STEP 3: Substitute y=80 in either equation to solve for x x+y=178 x+80=178 subtract 80 from both sides x=98 pounds of type A coffee ANSWER: x=98 pounds of type A coffee y= 80 pounds of type B coffee CHECK: Substitute answers for x & y into either equation to be sure it checks. 5.45x+4.20y=870.10 5.45(98)+4.20(80)=870.10 534.10+336=870.10 870.10=870.10 Hope this helps! :)
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