Boris's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Boris
1 answer:
X=pounds of Type A coffee
y=pounds of Type B coffee
QUANTITY EQUATION:
x+y=178
COST EQUATION:
$5.45x + $4.20y=$870.10
STEP 1:
Solve for one variable in equation one. Then substitute it in equation two.
x+y=178
subtract y from both sides of the equation
x=178-y
STEP 2:
substitute x=178-y in equation two
5.45x + 4.20y=870.10
5.45(178-y) + 4.20y=870.10
multiply 5.45 by everything in parentheses
(5.45*178)+(5.45*-y)+4.20y=870.10
970.10-5.45y+4.20y=870.10
combine like terms
970.10-1.25y=870.10
subtract 970.10 from both sides
-1.25y=-100
divide both sides by -1.25
y=80 pounds of type B coffee
STEP 3:
Substitute y=80 in either equation to solve for x
x+y=178
x+80=178
subtract 80 from both sides
x=98 pounds of type A coffee
ANSWER:
x=98 pounds of type A coffee
y= 80 pounds of type B coffee
CHECK:
Substitute answers for x & y into either equation to be sure it checks.
5.45x+4.20y=870.10
5.45(98)+4.20(80)=870.10
534.10+336=870.10
870.10=870.10
Hope this helps! :)
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