$x^2+(x+1)^2=61\\ x^2+x^2+2x+1-61=0\\ 2x^2+2x-60=0\ \ /:2\\ x^2+x-30=0\\ \Delta=1^2-4\cdot(-40)=1+120=121\ \ \Rightarrow\ \ \sqrt{\Delta} =11\\ \\ x_1= \frac{-1-11}{2} = \frac{-12}{2} =-6,\ \ \ \ x_2= \frac{-1+11}{2} = \frac{10}{2}=5\\ \\Ans.:x=-6$

3 0

4 years ago

The function f(x) = 20(3)^x represents the growth of a fish population every year in a local lake. Jesse wants to manipulate the

valentina_108 [34]

We need the exponents law

$a^{bx}=(a^b)^x$
So if
a=3
b=1/2

then
$3^{1/2*x}=(3^{1/2})^x$
where x represent every half a year.

3 0

4 years ago

Read 2 more answers

Plz help if possible

mestny [16]

The answer is (1,3).....

4 0

4 years ago

Read 2 more answers

Urgent help! can someone answer these questions for me?

pantera1 [17]

Answer:

she needs 600 g chocolate. He needs 150 g flour. his recipe is for 6 people

4 0

4 years ago