Answer:
a)
b)
c)
Step-by-step explanation:
<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.
This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.
Then write the polynomial in factored form.
Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.
<u>For question b, do the same procedure</u>.
Degree: 3
Zeros: -5/2, 4/5, 6.
The factors are
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<u>Finally for the question c we have</u>
Degree: 5
Zeros: -3, 1, 4, -1
Multiplicity 2 in -1
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99 is 1 less than 100.
(100-1)×6
100×6=600
-1×6=-6
600-6=<span>594
Answer: 594</span>
Y = 2x + 2
Y = 2x -
Subtract
0 = 2
This makes no sense meaning the lines are parallel. Therefore there are 0 solutions.