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Vilka [71]
3 years ago
5

The _____________________________________ Postulate says that If two angles of one triangle are congruent to two angles of anoth

er triangle, then the triangles are similar.
Mathematics
1 answer:
Crank3 years ago
7 0

Answer: Angle sum

Step-by-step explanation:

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Write an equation in slope intercept form for the line that passes through (3, 5) and is perpendicular to the line whose equatio
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3 years ago
The  area of triangle formed by points of intersection of parabola y=a(x+5)(x−1) with the coordinate axes is 12. Find a if it is
Pie

We know that the points at which the parabola intersects the x axis are

(-5,0) and (1,0)

So the extent between these two points would be the base of the triangle

lets find the length of the base using the distance formula

\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}

the base b=6

We will get the height of the triangle when we put x=0 in the equation

y=a(0+5)(0-1)

y=-5a

so height = -5a (we take +5a since it is the height)

We know that the area of the triangle =

\frac{1}{2} × 6 × (5a) = 12

15a=12

a= \frac{4}{5}


7 0
3 years ago
Draw a model to subtract 2 2/5 -1 8/10
Igoryamba

See picture for reply and solution steps.

6 0
3 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
LenaWriter [7]
Easy peasy


the average rate of change in section A is the slope from (1,g(1)) to (2,g(2))
the average rate of chagne in section B is the slope from (3,g(3)) to (4,g(4))



A.

section A
g(1)=4(3)^1=12
g(2)=4(3)^2=4(9)=36
slope=(36-12)/(2-1)=24/1=24

section B
g(3)=4(3)^3=4(27)=108
g(4)=4(3)^4=4(81)=324
slope=(324-108)/(4-3)=216/1=216



section A has an average rate of change of 24
section B has an average rate of change of 216
3 0
3 years ago
Help ! Please !!!!!!!!!!!!!!
Ostrovityanka [42]

Answer:

12a^6b^3 you multiply 4 and 3 to get 12,then you factor out the algebra with the common terms.

4 0
3 years ago
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