Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
The answer to your question is:
Step-by-step explanation:
Factorize 
Factorize 
Simplify 
Answer:
180°
Step-by-step explanation:
JM is the diameter of the circle with center L.
Yes, Lynn does have enough for each classmate in class, If she wants to give each kid 1/4 of a candy bar, 4(the amount of kids that can get candy per bar) x8(candy bars) would equal 32.
