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ArbitrLikvidat [17]
3 years ago
8

HELPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
sashaice [31]3 years ago
7 0
The answer I got is 8

dybincka [34]3 years ago
4 0
8 is the answer I got
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soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of 2\pi and a vertical compression.

Step-by-step explanation:

We are given the parent function as y= \cot x

It is given that, transformations are applied to the parent function in order to obtain the function y=0.5\cot (0.5x) i.e. y=\frac{1}{2}\cot (\frac{x}{2})

That is, we see that,

The parent function y= \cot x is stretched horizontally by the factor of \frac{1}{2} which gives the function y=\cot (\frac{x}{2}).

Further, the function is compressed vertically by the factor of \frac{1}{2} which gives the function y=\frac{1}{2}\cot (\frac{x}{2}).

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period \frac{P}{|b|}.

Since, the period of y= \cot x is \pi, so the period of y=\frac{1}{2}\cot (\frac{x}{2}) is \frac{\pi}{1/2} = 2\pi

Hence, we get option C is correct.

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3 years ago
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Find the values of the variables in the parallelogram. The diagram is not to scale.
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Factor this expression as a difference of squares: 4-(2a+3b)^2
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Take a look at the attachment to see how I got this solution. 

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