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2 years ago

10

Factor this expression as a difference of squares: 4-(2a+3b)^2

1 answer:

Nadya [2.5K]2 years ago

7 0

The complete factorized expression is (2 + 2a + 3b) (2 - 2a + 3b).
Take a look at the attachment to see how I got this solution.

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35 POINTS: TRIGONOMETRY: Find each side marked with a letter. All lengths are in centimetres. kindly include the working since I

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

4 0

2 years ago

How do you divide this as a mixed number. <br> - 2/3 ÷ (- 1/2)

dezoksy [38]

Recipricol the -1/2 to 2 and change the sign to multiply
-2/3 x 2 = -4/3
-4/3 = -1 1/3

-1 1/3 is your answer

hope this helps

3 0

2 years ago

Read 2 more answers

Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
$\implies V_{cone} = V_{sphere}$

$\implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}$

$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

$\implies x= \sqrt[3]{\frac{8}{3^2}}$

$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

$\because r = 3x$

$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

Taking antilog on both sides, we find:

$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

$\implies 2\times \sqrt [3]3 = 2.88$

8 0

1 year ago

What integer values satisfy both inequalities? − 2 < x < 3 − 2 ≤ x < 2

NARA [144]

Given:

The inequalities are:

$-2$

$-2\leq x$

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

$-2$

$-2\leq x$

For $-2$ , the possible integer values are

$x=-1,0,1,2$ ...(i)

For $-2\leq x$ , the possible integer values are

$x=-2,-1,0,1$ ...(ii)

The common values of x in (i) and (ii) are

$x=-1,0,1$

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

6 0

2 years ago

Help me with this equation please

vivado [14]

Answer:

Step-by-step explanation:

7 0

1 year ago