Answer:
its c jei2ueueuu2eueueu2u2u2
Answer:
- a) x+y
- b) 2x+y
- c) -x
- d) x+y+1
- e) y-x
- f) x/2
Step-by-step explanation:
The applicable rules of logarithms are ...
log(ab) = log(a) +log(b)
log(a^b) = b·log(a)
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![\text{a) }\log{6}=\log{(2\cdot 3)}=\log{2}+\log{{3}=\boxed{x+y}](https://tex.z-dn.net/?f=%5Ctext%7Ba%29%20%20%7D%5Clog%7B6%7D%3D%5Clog%7B%282%5Ccdot%203%29%7D%3D%5Clog%7B2%7D%2B%5Clog%7B%7B3%7D%3D%5Cboxed%7Bx%2By%7D)
![\text{b) }\log{12}=\log{(2^23)}=2\log{2}+\log{3}=\boxed{2x+y}](https://tex.z-dn.net/?f=%5Ctext%7Bb%29%20%20%7D%5Clog%7B12%7D%3D%5Clog%7B%282%5E23%29%7D%3D2%5Clog%7B2%7D%2B%5Clog%7B3%7D%3D%5Cboxed%7B2x%2By%7D)
![\text{c) }\log{(1/2)}=\log{2^{-1}}=-\log{2}=\boxed{-x}](https://tex.z-dn.net/?f=%5Ctext%7Bc%29%20%20%7D%5Clog%7B%281%2F2%29%7D%3D%5Clog%7B2%5E%7B-1%7D%7D%3D-%5Clog%7B2%7D%3D%5Cboxed%7B-x%7D)
![\text{d) }\log{60}=\log{(2\cdot 3\cdot 10)}=\log{2}+\log{3}+\log{10}=\boxed{x+y+1}](https://tex.z-dn.net/?f=%5Ctext%7Bd%29%20%20%7D%5Clog%7B60%7D%3D%5Clog%7B%282%5Ccdot%203%5Ccdot%2010%29%7D%3D%5Clog%7B2%7D%2B%5Clog%7B3%7D%2B%5Clog%7B10%7D%3D%5Cboxed%7Bx%2By%2B1%7D)
![\text{e) }\log{1.5}=\log{3\cdot2^{-1}}=\log{3}-\log{2}=\boxed{y-x}](https://tex.z-dn.net/?f=%5Ctext%7Be%29%20%20%7D%5Clog%7B1.5%7D%3D%5Clog%7B3%5Ccdot2%5E%7B-1%7D%7D%3D%5Clog%7B3%7D-%5Clog%7B2%7D%3D%5Cboxed%7By-x%7D)
![\text{f) }\log{\sqrt{2}}=\log{2^{\frac{1}{2}}}=\dfrac{1}{2}\log{2}=\boxed{\dfrac{x}{2}}](https://tex.z-dn.net/?f=%5Ctext%7Bf%29%20%20%7D%5Clog%7B%5Csqrt%7B2%7D%7D%3D%5Clog%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Clog%7B2%7D%3D%5Cboxed%7B%5Cdfrac%7Bx%7D%7B2%7D%7D)
sub 2 for any "x"
3(2)^2-2(2)+1
6^2-4+1 i dont know if you need to simplify even more but if you do
36-4+1 32+1 31
i hope this helps you!
A statement or proposition which is regarded as being established, accepted, or self-evidently true