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3 years ago

13

Researches find that there are 60 raccoons on a island when they return a year later they find there are 84. What is the annual

population growth rate for raccoons

1 answer:

Anon25 [30]3 years ago

8 0

(84-60/60) x 100 (new population-original population / original) x 100 =40% growth

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A parabola can be drawn given a focus of (6,0) and a directrix of y = -6. Write the

VLD [36.1K]

Answer:

Equation of the parabola: $12y+36=(x-6)^2$ or $y=\frac{x^2}{12} -x$

Vertex form: $y=\frac{1}{12} (x-6)^2-3$

Intercept form: $y=\frac{x}{12} (x-12)$

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3 years ago

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Find the annual percentage rate of change for the population of Oregon. In 2000, there were 4.8

MrRa [10]

Answer:

The annual percentage rate of change for the population of Oregon is of 8.125%.

Step-by-step explanation:

Total percentage change:

Change multiplied by 100 and divided by the initial value.

Change: 8.7 - 4.8 = 3.9 million

Initial value: 4.8

Percentage change: 3.9*100/4.8 = 81.25%

Annual percentage rate of change

81.25% during 10 years(from 2000 to 2010).

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81.25%/10 = 8.125%

The annual percentage rate of change for the population of Oregon is of 8.125%.

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2 years ago

Hello! Please help me with this. I'm very desperate lol. Its 16. Ill give brainliest

Paladinen [302]

Answer:

You showed the right work and got the right answer!

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Step-by-step explanation:

Since B is in the middle of A and C, AB + BC = AC

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1 year ago

-8(3 - 4v) + 8v = 9v + 3 what is the answer?

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2 years ago

Stephen & Richard share a lottery win of £2950 in the ratio 2 : 3. Stephen then shares his part between himself, his wife &a

horsena [70]

Answer:

Stephen's wife got £354 more than his son.

Step-by-step explanation:

Given:

Amount of Lottery = £2950

Now Given:

Stephen & Richard share a lottery amount in the ratio 2 : 3

Let the common factor between them be 'x'.

So we can say that;

$2x+3x=2950\\\\5x = 2950$

Dividing both side by 5 we get;

$\frac{5x}{5}=\frac{2950}{5}\\\\x = 590$

So we can say that;

Stephen share would be = $2x =2\times 590 = \£1180$

Now Given:

Stephen then shares his part between himself, his wife & their son in the ratio 3 : 5 : 2.

Let the common factor between them be 'y'.

So we can say that;

$3y+5y+2y=1180\\\\10y=1180$

Dividing both side by 10 we get;

$\frac{10y}{10}=\frac{1180}{10}\\\\y=118$

So Stephen's wife share = $5y = 5\times 118= \£590$

And Stephen's son share = $2y=2\times118 =\£236$

Now we need to find how much more her wife got then her son.

To find how much more her wife got than her son we will subtract Stephen's son share from Stephen's wife share.

framing in equation form we get;

Amount more her wife got than her son = $590-236 = \£354$

Hence Stephen's wife got £354 more than his son.

3 0

3 years ago