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romanna [79]
3 years ago
13

Researches find that there are 60 raccoons on a island when they return a year later they find there are 84. What is the annual

population growth rate for raccoons
Mathematics
1 answer:
Anon25 [30]3 years ago
8 0
(84-60/60) x 100 (new population-original population / original)  x 100 =40% growth
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Find the product or quotient. Express using positive exponents
Alex73 [517]

Answer:

c

Step-by-step explanation:

x^{-6}*x^{-5}=x^{(-6)+(-5)}=x^{-11}=\frac{1}{x^{11}}

x^{a}*x^{b}=x^{a+b}\\\\x^{-a}=\frac{1}{x^{a}}

6 0
3 years ago
Hey guys please help find the area
V125BC [204]

Answer:

70.15 ft²

Step-by-step explanation:

The figure consists of two adjacent equilateral triangles (all angles are 60 degrees and all outer edges are 9 ft).

If we focus on one of these equilateral triangles, we can get the final area by multiplying the area of that one triangle by 2.

The formula for the area of a triangle is (1/2)(base)(height).  Remembering to multiply this by 2, we get

area of figure = (base)(height)

                                             √3

                       = (9 ft)(9 ft)(--------) = (81 ft²)(1.732) = 70.15 ft²

                                               2

4 0
3 years ago
Can someone please send help :(
nlexa [21]
(f o g)(x)

g(x) = x + 2

Since it’s telling you to use g(x), you use (x + 2) as your new x value for function f.

f(x + 2) = 5(x + 2) + 5
= 5x + 10 + 5
= 5x + 15

5 0
3 years ago
Which graph shows the function y=(13)3x
Aleks04 [339]
Answer: in da pic

Explanation: Can’t see pic but I used mathwye to graph it

6 0
2 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
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