25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Add all of them and them subtract by the value
Multiply the price by the 5% by turning the percent into a decimal.
5% = 0.05
45.90 x 0.05 = $2.295
Which can be rounded to 2.30 if needed.
Step-by-step explanation:
The answer is letter B. Negative and Negative is Positive.
Answer:
153.94
Step-by-step explanation:
A = pi * r^2
A = pi * 7^2 (radius is half of the diameter)
A = 49 * pi
A = 153.94
i hope this helps !!
