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aniked [119]
3 years ago
15

Enter the unknown the value that makes this statement true: 30% of _____ is 60.

Mathematics
1 answer:
mina [271]3 years ago
4 0
The answer of the unknown value is 90%

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Given the equation 8x = 4y + 16, generate a plan to rewrite it in slope intercept form. Which variable do you solve for?
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Answer:

y = 2x-4

Step-by-step explanation:

To put the equation in slope intercept form (y=mx+b), we solve the equation for y

8x = 4y +16

Subtract 16 from each side

8x - 16 = 4y+16-16

8x-16 = 4y

Divide each side by 4

8x/4 -16/4 = 4y/4

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1. Use separation of variables to find the solution to the differential equation subject to the given initial condition.
andrew11 [14]

Answer:

Step-by-step explanation:

Given the differential equation dy/dx = 5y/x subject to the condition y = 4 and x = 1. Using the variable separable method of solving differential equation, we will have;

dy/dx = 5y/x

Separate the variables

dy/5y = dx/x

Integrate both sides of the expression

\frac{1}{5}\int\limits \frac{1}{y}  \, dy = \int\limits \frac{dx}{x} \\ \\\frac{1}{5}lny = lnx + C\\\\lny = 5lnx+5C\\

using the initial condition y = 4 while x = 1

ln4 = 5ln1 + 5C

ln4 = 0+5C

C = ln4/5

Substituting the value of C back into the expression;

lny = 5 lnx+5(ln4/5)\\lny = 5lnx+ln4\\lny = lnx^5+ln4\\lny = ln(4x^5)\\y = 4x^5

<em>Hence the solution to the differential equation is y = 4x⁵</em>

<em></em>

b) Given 4(du/dt) = u²

du/dt = u²/4

du/ u² = dt/4

u⁻²du = 1/4 dt

integrate both sides of the equation

\int\limit {u^{-2}} \, du  = \int\limits\frac{1}{4}  \, dt\\\\\frac{u^{-1}}{-1} = \frac{t}{4} + C\\\\\frac{-1}{u} =  \frac{t}{4} + C

Imputing the initial condition u(0) = 7 i.e when t = 0, u = 7

\frac{-1}{7} =  \frac{0}{4} + C\\\\\frac{-1}{7} =  C\\

\frac{-1}{u} =  \frac{t}{4} - \frac{1}{7}

<em>Hence the solution to the DE is </em>\frac{-1}{u} =  \frac{t}{4} - \frac{1}{7}

6 0
3 years ago
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