The answer is:
![y = x^{2} + 6](https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B2%7D%20%20%2B%206)
EXPLANATION
I dunno, this is just a technique. I believe you know that the vertex form of a quadratic equation is
![y = a(x - h)^{2} + k](https://tex.z-dn.net/?f=y%20%3D%20a%28x%20-%20h%29%5E%7B2%7D%20%2B%20k)
Referring to the given vertex, you have (0,6). So, h should be 0 and k should be 6.
You can see that h is absent in the last two equations given that it is only x^2 and not x minus h.
Going to k, we can find that only the third equation has fulfilled a positive k (the fourth has -6).
In problems like this, I think you can already manage that easy to choose which among the quadratic equations show a particular vertex.
Solution: We are given:
![Mean =78, Standard-deviation =6.3](https://tex.z-dn.net/?f=Mean%20%3D78%2C%20Standard-deviation%20%3D6.3)
We know that a usual values of the test scores falls within 2 standard deviation from the mean.
Therefore, the minimum usual test score is:
![Mean - 2 Standard-deviation](https://tex.z-dn.net/?f=Mean%20-%202%20Standard-deviation)
![78-2 \times 6.3](https://tex.z-dn.net/?f=78-2%20%5Ctimes%206.3)
![78-12.6](https://tex.z-dn.net/?f=78-12.6)
![65.4](https://tex.z-dn.net/?f=65.4)
The maximum usual test score is:
![Mean + 2 Standard-deviation](https://tex.z-dn.net/?f=Mean%20%2B%202%20Standard-deviation)
![78+2 \times 6.3](https://tex.z-dn.net/?f=78%2B2%20%5Ctimes%206.3)
![78+12.6](https://tex.z-dn.net/?f=78%2B12.6)
![90.6](https://tex.z-dn.net/?f=90.6)
Therefore, the minimum and maximum “usual” values of the test scores are:
65.4 and 90.6
Answer:
Z/X
Step-by-step explanation:
cause sin is p/h and p=Z and h=X
The answer would be=22.9n
Answer:
I really don't know just answering to get points