B is true
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The one time investment of $1000 would worth $10285.72 after 40 years at 6% rate of return
What is annual compounding?
Annual compounding means that the number of times interest is compounded annually is once, compared to semiannual compounding where the interest on the investment is calculated twice a year.
The worth of the investment after 40 years means its future value after having invested $1000 for 40 years using the below formula for future value of a single cash flow:
FV=PV*(1+r)^N
FV=future worth of investment=unknown
PV=initial investment=$1000
r=rate of return=6%
N=number of years of investment=40
FV=$1000*(1+6%)^40
FV=$1000*1.06^40
FV=$1000* 10.2857179371259
FV=$10285.72
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Answer:
y = -2
Step-by-step explanation:
10 -5y = 20 { subtract 10 from both sides}
-5y = 20 - 10
-5y = 10 {Divide both sides by (-5) }
y = 10/-5
y = -2
The two consecutive integers are 2 and 3
<em><u>Solution:</u></em>
Let x and x + 1 are the two consecutive integers
Let "x" be the smallest integer
Let "x + 1" be the larger integer
<em><u>Given that, sum of 2 consecutive integers is one less than 3 times the smaller integer</u></em>
Therefore,
sum of 2 consecutive integers = one less than 3 times the smaller integer
sum of 2 consecutive integers = 3 times the smaller integer - 1
x + x + 1 = 3(x) - 1
2x + 1 = 3x - 1
3x - 2x = 1 + 1
x = 2
Thus the smaller integer = x = 2
Larger integer = x + 1 = 2 + 1 = 3
Thus the two consecutive integers are 2 and 3