Answer:

Step-by-step explanation:
A quadratic polynomial is given to us and we need to find its factorised form . The given quadratic polynomial is ,
And this equation is similar to the equation in ax² + bx + c form . So in order to factorise it .
Step 1: <u>Multiply </u><u>the </u><u>coefficient </u><u>of </u><u>x²</u><u> </u><u>with </u><u>the </u><u>constant</u><u> </u><u>term </u><u>.</u>
Here the coefficient of x² is 12 and the constant term is 1 . So on multiplying them we get 12*1= 12 .
Step 2: <u>Look </u><u>out</u><u> </u><u>for </u><u>the </u><u>possible</u><u> </u><u>factors </u><u>of </u><u>the </u><u>number</u><u> </u><u>.</u>
Here the obtained number is 12 . So the possible factors of 12 is
- 1 *12
- -1*-12
- 2*6
- -2*-6
- 4*3
- -4*-3
Step3: <u>Choose </u><u>the </u><u>factor </u><u>whose </u><u>sum </u><u>is </u><u>equal </u><u>to </u><u>the </u><u>coefficient</u><u> </u><u>of </u><u>the </u><u>middle</u><u> </u><u>term </u><u>.</u>
Here we can see that the middle term is 7 . And the sum of 4 and 3 is equal to 7 . Hence here we will break 7x as 4x + 3x .
Step 4: <u>After </u><u>proper</u><u> </u><u>arrangements</u><u> </u><u>take </u><u>out</u><u> the</u><u> </u><u>common</u><u> </u><u>term </u><u>and </u><u>then </u><u>factorise</u><u>.</u>
After suitable rearrangment we get ,

Answer:
x = 3
Step-by-step explanation:
5x - 2 = 3x + 4
2x = 6
x = 3
Answer:
The required answer is
Therefore the number in green box should be 7.
Step-by-step explanation:
Given:
AB = 7√2
AD = a , BD = b , DC = c , AC = d
∠B = 45°, ∠C = 30°
To Find:
c = ?
Solution:
In Right Angle Triangle ABD Sine identity we have

Substituting the values we get


Now in Triangle ADC Tangent identity we have

Substituting the values we get

The required answer is
I’m not 100% but my best guess is 20.
X = 9
Work:
5x-3+48+90=180 (sum)
-3+48+90=135
135+5x=180
subtract 135 from 135 and 180 and that gives you 45
5x=45
divide each side by 5
x=9