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2 years ago

Factor completely x2 − 36

Mathematics

1 answer:

Hoochie [10]2 years ago

5 0

X² - 36 = x² - 6² = (x-6)(x+6)

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May someone help me with B) Thank you so much ❤❤

Tom [10]

180 degrees - 116 degrees =64 degrees (angle PDC)

180 degrees - 64 degrees = 116 degrees (angle APD)

3 0

3 years ago

31-27+12-23-(-25)+(-6)=

lubasha [3.4K]

31-27+12-23-(-25)+(-6)= 12

4 0

3 years ago

Read 2 more answers

Thee questionn is beloww

Phantasy [73]

Given:

$m\angle ABC=60$

To find:

The $m\angle ADC$ .

Solution:

In circle B, $\angle ABC$ is central angle and $\angle ADC$ is inscribed angle from two points A and C.

According to central angle theorem, central angle is always twice of inscribed angle.

$m\angle ABC=2(m\angle ADC)$ [Central angle theorem]

$60=2(m\angle ADC)$

Divide both sides by 2.

$\dfrac{60}{2}=m\angle ADC$

$30=m\angle ADC$

Therefore, $m\angle ADC=30$ .

6 0

2 years ago

Given h(×) =-3×+2,solve for x when h (×)=-4

MakcuM [25]

Answer:14

Step-by-step explanation:

h(x)=-3x+2

h(-4)=-3(-4)+2

h(-4)=12+2

h(-4)=14

7 0

3 years ago

Read 2 more answers

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago