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pantera1 [17]
3 years ago
14

The weights of four packets of sugar are shown below: Packet A: 4.42 pounds Packet B: 4.34 pounds Packet C: 4.44 pounds Packet D

: 4.39 pounds Sue has a scale that measures to the nearest tenth of a pound. If Sue weighs each packet on her scale, the lightest reading will be _____ pounds. Answer for Blank 1:
Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

4.3

Step-by-step explanation:

Since her scale only shows tenths, the weights of the packets will be

Packet A - 4.4

Packet B - 4.3

Packet C - 4.4

Packet D - 4.4 since 9 rounds 3 up to 4

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AVprozaik [17]

ΔACD and ΔASR are the same so we can write a ratio:

x/4 = 10/5

x/4 = 2

x/4 * 4 = 2 * 4

x = 8

Since AS is equal to x, they are both the same.

Therefore, the answer is [ x = 8, AS = 8 ]

Best of Luck!

6 0
3 years ago
Read 2 more answers
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
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What triangle can be obtuse?
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Answer:

Isosceles and scalene triangles can both be obtuse.

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Answer:

Correct my guy or gal.

Step-by-step explanation:

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Work out the total surface area of this hemisphere which has a radius of 8cm.
Masja [62]

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} r=8 \end{cases}\implies SA=4\pi (8)^2\implies SA=256\pi \\\\\\ \stackrel{\textit{half of that for a \underline{hemi}sphere}}{\cfrac{256\pi }{2}\implies 128\pi \implies }\stackrel{\textit{rounded up}}{402.1}

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3 years ago
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