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pantera1 [17]
2 years ago
14

The weights of four packets of sugar are shown below: Packet A: 4.42 pounds Packet B: 4.34 pounds Packet C: 4.44 pounds Packet D

: 4.39 pounds Sue has a scale that measures to the nearest tenth of a pound. If Sue weighs each packet on her scale, the lightest reading will be _____ pounds. Answer for Blank 1:
Mathematics
1 answer:
Kruka [31]2 years ago
7 0

Answer:

4.3

Step-by-step explanation:

Since her scale only shows tenths, the weights of the packets will be

Packet A - 4.4

Packet B - 4.3

Packet C - 4.4

Packet D - 4.4 since 9 rounds 3 up to 4

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Answer:

3/4

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three children each ate 1/4 of a candy bar.Whitch expression shows how you would solve for the totalamount of candy bar that was
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Solve the following system of equations graphically.<br> y=3x+4<br> y=-2x-5
ExtremeBDS [4]

Answer:

 (x, y) = (-1.8, -1.4)

Step-by-step explanation:

3 0
2 years ago
Answers plz i cant do math
Licemer1 [7]

The slope of all parallel lines are equal.

The slope of a line in the form y=mx+c is m.

1. The given equation is: y=4x+2.  The slope of this line is m=4. The slope of the line parallel to this line is also 4.

2. The given equation is y=\frac{2}{7}x+1. The slope of this line is m=\frac{2}{7}.

The slope of the line parallel to it is also \frac{2}{7}.

3. The next equation is y+9x=13. The slope intercept form is y=-9x+13.

The slope of this is m=-13. The line parallel to it also has slope which is -13.

4. The given equation is y=-\frac{1}{2}x+4. The slope of this line and the line parallel to it is m=-\frac{1}{2}

5. The equation is 6x+2y=4. We simplify to get: 3x+y=2.

The slope-intercept form is y=-3x+2. The line parallel to this line has slope m=-3

6. Assuming the line is y=-3x+9, then the slope is m=-3

7. Assuming the line is -5x+5y=4, then the slope-intercept form is y=x+\frac{4}{5} and the slope of the line parallel to this line is m=1

8. The equation is 9x-5y=4. The slope intercept form is y=\frac{5}{9}x-\frac{4}{9}. The slope of the line parallel to this line is m=\frac{5}{9}

9. The given equation is -x+3y=6. The slope intercept form is y=\frac{1}{3}x+2. The line  parallel to this line also has slopem=\frac{1}{3}.

10.  Assuming the given line is 6x-7y=10, then y=\frac{6}{7}x-\frac{10}{7} and the line parallel to it has slope m=\frac{6}{7}

11. Assuming the line is y-x=-3, then y=x-3 and the slope of the line parallel to it is m=1

12. The given line is 3x-5y=6. This implies that y=\frac{3}{5}x-\frac{6}{5}

7 0
3 years ago
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choli [55]

Answer:

Sin(F)  = 12/13

Cos(F)  = 5/13

Tan(F) = 12/5

Step-by-step explanation:

Sin = Opp./Hypo, Cos = Adj./Hypo. and Tan = Opp./Adj.

So

Sin(F) = Opp./Hypo = 12/13

Cos(F) = Adj./Hypo = 5/13

Tan(F) = Opp./Adj. = 12/5

7 0
3 years ago
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