Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
First isolate y by adding x to both sides in y-x=3 and getting y=x+3
Step 1: substitute x+3 for y in 3y=x+6 to get 3(x+3)=x+6
Step 2: distribute 3x+9=x+6
Step 3: subtract like terms 2x=-3
Step 4: divide x=-3/2
substitute -3/2 for x in y=x+3 to get
y=-3/2+3
y=3/2
answer: y=3/2 x=-3/2
Answer:
B
Step-by-step explanation:
...
Answer:
The answer to your question is -27/20
Step-by-step explanation:
Divide 3/5 ÷ - 4/9
Process
1.- Just multiply the numerator of the first fraction by the denominator of the second fraction.
3 x - 9 = -27
2.- Multiply the denominator of the first fraction by the numerator of the second fraction.
5 x 4 = 20
3.- Join both results
-27/20
