2 years ago

Using a common denominator to write an equivalent fraction for 3/7?

2 answers:

5 0

I'm not sure exactly what you are trying to ask, but you can multiply the numerator and denominator by any number and it will stay the same value fraction, as long as you are multiplying them both by the same number.

Nutka1998 [239]2 years ago

4 0

6/14

Multiply both 3 and 7 by 2, this gives you equivalent fractions (there are more possible equivalent equations of course)

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(e+8)° (3e-4° Need help asap thx

julsineya [31]

Answer:

e=44°

Step-by-step explanation:

3e-4+e+8 = 180 degree (being linear pair)

4e+4=180

4e=180-4

4e=176

e=176/4

e=44 degree

7 0

3 years ago

Read 2 more answers

If ON is a midsegment of KLM, find LM. A.2 B.3 C.4 D.5

Aleksandr-060686 [28]

NO is 2 times LM

2(x+1) = 4x

2x + 2 = 4x

2 = 2x

1 = x

Plug that in for 4x

4(1)

4

4 0

3 years ago

Read 2 more answers

Have no idea how to do this-- Could someone show me how please.

motikmotik

Answer:

well E is (-7,-7) F is (-2,-3) G is (-1,-6)

Step-by-step explanation:

7 0

3 years ago

How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1

kramer

$2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)$

Since $\sin^2x+\cos^2x=1$ , you have

$2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)=2\sec^2x\cos^2x-1$

and since $\sec x=\dfrac1{\cos x}$ , you end up with $2-1=1$ .

6 0

3 years ago

X=-12-6y -4x+5y=-39 slove by the system of substitution

Artist 52 [7]

X = -6y - 12
4x + 5y =-39

4x + 5y = -39
-4(-6y - 12) + 5y = -39
-4(-6y) + 4(12) + 5y = -39
24y + 48 + 5y = -39
29y + 48 = -39
29y = -87
y = -3

x = -6y - 12
x = -6(-3) - 12
x = 28 - 12
x = 6

(x, y) = (6, -3)

5 0

3 years ago