Answer:
you find the square root of two and add it to 3.14. Then you find the square root of 5. after that you divide the top by the bottom and you have your answer
Step-by-step explanation:
The correct answer would be 2.0
Answer:
B
Step-by-step explanation:
is you do 18÷1.95=9.2 which is just 9 rounded up.
Answer:
1. 792 2. 20. 3. 126. 4.1995840
Step-by-step explanation:
Use the formula C(n,r)= n!/ r/ (n-r)! where n is total quantity of varieties and r is the quantity uou should choose.
1) n=12 (total quantity); r= 7
C(12,7)= 12!/(7! *(12-7)!)= 8*9*10*11*12/ (5*4*3*2)= 8*9*11= 72*11= 792
2) n=6 r=3
C(6,3)= 6!/ (3! * (6-3)!)= 6!/ (3!)^2= 4*5*6/ 3*2= 20.
3) C(9,5)= 9!/ (5!*4!)= 6*7*8*9/ (4*3*2*1)= 2*63= 126
4) You need to choose the whole set which consists of three components that has been defined. Multiply previous results
792*20*126= 1995840.
the idea behind the recurring decimal as a fraction, is to first off, multiply or divide by some power of 10, in order that we leave the recurring decimal to the right of the decimal point.
then we multiply by a power of 10, in order to move the repeating digits to the left of the decimal point, anyhow, let's proceed.
![\bf 0.6\overline{1212}\implies \cfrac{06.\overline{1212}}{10}\implies \cfrac{6+0.\overline{1212}}{10}\qquad \qquad \stackrel{\textit{now let's make}}{x=0.\overline{1212}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llll} 100\cdot x &=& 12.\overline{1212}\\\\ &&12+0.\overline{1212}\\\\ &&12+x\\\\ 100x&=&12+x\\\\ 99x&=&12\\\\ x&=&\cfrac{12}{99}\implies x = \cfrac{4}{33} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%200.6%5Coverline%7B1212%7D%5Cimplies%20%5Ccfrac%7B06.%5Coverline%7B1212%7D%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B6%2B0.%5Coverline%7B1212%7D%7D%7B10%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bnow%20let%27s%20make%7D%7D%7Bx%3D0.%5Coverline%7B1212%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20100%5Ccdot%20x%20%26%3D%26%2012.%5Coverline%7B1212%7D%5C%5C%5C%5C%20%26%2612%2B0.%5Coverline%7B1212%7D%5C%5C%5C%5C%20%26%2612%2Bx%5C%5C%5C%5C%20100x%26%3D%2612%2Bx%5C%5C%5C%5C%2099x%26%3D%2612%5C%5C%5C%5C%20x%26%3D%26%5Ccfrac%7B12%7D%7B99%7D%5Cimplies%20x%20%3D%20%5Ccfrac%7B4%7D%7B33%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \cfrac{06.\overline{1212}}{10}\implies \cfrac{6+x}{10}\implies \cfrac{6+\frac{4}{33}}{10}\implies \cfrac{~~\frac{202}{33}~~}{10}\implies \cfrac{~~\frac{202}{33}~~}{\frac{10}{1}}\implies \cfrac{202}{330} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{101}{165}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B06.%5Coverline%7B1212%7D%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B6%2Bx%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B6%2B%5Cfrac%7B4%7D%7B33%7D%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B~~%5Cfrac%7B202%7D%7B33%7D~~%7D%7B10%7D%5Cimplies%20%5Ccfrac%7B~~%5Cfrac%7B202%7D%7B33%7D~~%7D%7B%5Cfrac%7B10%7D%7B1%7D%7D%5Cimplies%20%5Ccfrac%7B202%7D%7B330%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Ccfrac%7B101%7D%7B165%7D~%5Chfill)
notice, we first divided by 10, to move the decimal point over to the right by 1 slot, then we multiplied by 100, to move it two digits over the decimal point, namely the repeating "12", thus we use 100.
First put a y in the place of f(x)
y = (1/3)^x
Then switch x and y
x = (1/3)^y
Solve for y
ln(x) = yln (1/3)
simplify
ln(x) = -ln(3)y
solve
y = -ln(x)/ln(3)
