6-3v=12 <br>What is the value of v? <br>A.) -6 <br>B.) -2 <br>C.) 2

Gloria talked on her cell phone for 320 minutes the first month,243 minutes the second month,and 489 minutes the third month.Her

34kurt

Answer: $\$175$

Step-by-step explanation:

Since Gloria cannot pay for each minute talked but for packages of 200 minutes at the rate of $25 each, we have to make calculations according to these conditions as follows:

Month 1:

Gloria talked on her cell phone for $320 min$ . So, she had to buy 2 packages of $200 min$ for $\$25$ each package.

Hence:

$(\$25) 2= \$50$

Month 2:

Gloria talked on her cell phone for $243 min$ . So, she had to buy again 2 packages of $200 min$ for $\$25$ each package.

Hence:

$(\$25) 2= \$50$

Month 3:

Gloria talked on her cell phone for $489 min$ . So, she had to buy 3 packages of $200 min$ for $\$25$ each package.

Hence:

$(\$25) 3= \$75$

Then, if we take the total Gloria had to pay for the frist three months, we have:

$\$50 + \$50 + \$75= \$175$

5 0

3 years ago

Find a decomposition of a=⟨−5,−1,1⟩ into a vector c parallel to b=⟨−6,0,6⟩ and a vector d perpendicular to b such that c+d=a.

dezoksy [38]

The projection of vector A <em>parallel</em> to vector B is $\langle -3, 0, 3\rangle$ and the projection of vector A <em>perpendicular</em> to vector B is $\langle -2, -1, -2\rangle$ .

In this question, we need to determine all projections of a vector with respect to another vector. In this case, the projection of vector A <em>parallel</em> to vector B is defined by this formula:

$\vec a_{\parallel , \vec b} = \frac{\vec a \,\bullet\,\vec b}{\|\vec b\|^{2}}\cdot \vec b$ (1)

Where $\|\vec b\|$ is the norm of vector B.

And the projection of vector A <em>perpendicular</em> to vector B is:

$\vec a_{\perp, \vec b} = \vec a - \vec a_{\parallel, \vec b}$ (2)

If we know that $a = \langle -5, -1, 1 \rangle$ and $\vec b = \langle -6, 0, 6 \rangle$ , then the projections are now calculated:

$\vec a_{\parallel, \vec b} = \frac{(-5)\cdot (-6)+(-1)\cdot (0)+(1)\cdot (6)}{(-6)^{2}+0^{2}+6^{2}} \cdot \langle -6, 0, 6 \rangle$

$\vec a_{\parallel, \vec b} = \frac{1}{2}\cdot \langle -6, 0, 6 \rangle$

$\vec a_{\parallel, \vec b} = \langle -3, 0, 3\rangle$

$\vec a_{\perp, \vec b} = \langle -5, -1, 1 \rangle - \langle -3, 0, 3 \rangle$

$\vec a_{\perp, \vec b} = \langle -2, -1, -2\rangle$

The projection of vector A <em>parallel</em> to vector B is $\langle -3, 0, 3\rangle$ and the projection of vector A <em>perpendicular</em> to vector B is $\langle -2, -1, -2\rangle$ .

We kindly invite to check this question on projection of vectors: brainly.com/question/24160729

7 0

3 years ago

A square piece of fabric has an area of (9x2 + 24x + 16) square inches. The length of each side of the fabric is (cx + d) in., w

horrorfan [7]

If the area of the square is 9x^+24x+16, then the side length wouldd be the square root of that. That would be 3x+4. The perimeter would be 4 times that so the perimeter is 4(3x+4) = 12x+16

Hope that helped

7 0

4 years ago

See file attached below:

serg [7]

Answer:

Goodluck my dude.

AnswwerrrdexxStep-by-step explanation:

Hi, the answer is goodlick.

5 0

3 years ago

Please help me answer this!!!!

garik1379 [7]