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Vanyuwa [196]
3 years ago
15

Ind the area of a circle whose circumference is 31.4 centimeters. Approximate Π as 3.14.

Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0
The circumference of a circle is found by 2(pi)•r. To find r, set this equal to the circumference they gave you.

31.4=2pi•r

Divide by 2pi

r=4.997

The area of a circle is given by pi•r^2

A=pi(4.997)^2

A=78.460 cm^2
dlinn [17]3 years ago
6 0
31.4/3.14=10
10/2=5
5*5*3.14= 78.5 cm square
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The numbers 0.23350 has how many significant figures?
Alenkinab [10]

Significant figures are the digits that carry meaning to its measurement. Significant figures includes all the numbers excluding all the leading zeros, trailing zeros. All non zero digits are significant. Zeros between the non zero digits are significant. In a decimal number, trailing zeros are significant.

Now, consider the given number 0.23350

Since, in a decimal number all the trailing zeros are significant.

So, in the number 0.23350 there are five significant figures 2,3,4,5 and 0.

Therefore, there are 5 significant figures in the given number.

3 0
3 years ago
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Find the vertex and the axis of symmetry of the graph of the function?
Orlov [11]
3) Vertex: (-7, 0) Axis of Symmetry: x=-7
6) Vertex: (-2, -1) Axis of Symmetry: x=-2
5 0
3 years ago
Plz help i will mark you branlyest also plz answer both questions
Margaret [11]

Answer:

D(1, -2)

E(3, -4)

4 0
3 years ago
Please answer this fast in two minutes now
Anuta_ua [19.1K]

Answer:

<h2>             18.3</h2>

Step-by-step explanation:

from cosines theorem:

t² = 11² + 14² - 2•11•14•cos87°

t² = 121 + 196 + 308•0.05236

t² = 333.12688

t = √333.12688

t = 18.2517... ≈ 18.3

7 0
3 years ago
hus, D satisfying ​(ABC)DequalsI exists. Why does the expression for D found above also satisfy ​D(ABC)equalsI​, thereby showing
Assoli18 [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

First Question

Option A is correct

Second  Question

Option C is correct

Third   Question

     D =  A^{-1}  *  B^{-1} *  C^{-1}

Fourth   Question

  So substituting for D in  (ABC) D =  I

                 (ABC) *  A^{-1}  *  B^{-1} *  C^{-1} =  I

                 I =  I

This proof that  ABC is invertible

Step-by-step explanation:

From the question we are told that

   A , B and  C are invertible which means that A^{-1} , B^{-1}, C^{-1} exist

Now

 From the question

          (ABC) D =  I

Where I is an identity matrix

   Now when we multiply both sides by  A^{-1}  we have

          A^{-1}  A BCD =  A^{-1} * I

          IBCD =  A^{-1}

Now when we multiply both sides by  B^{-1}  we have  

         B^{-1 } *I BCD =  A^{-1}  *  B^{-1}

         I CD =  A^{-1}  *  B^{-1}

Now when we multiply both sides by  C^{-1}  we have  

          C^{-1} * I CD =  A^{-1}  *  B^{-1} *  C^{-1}

              I D =  A^{-1}  *  B^{-1} *  C^{-1}

                 D =  A^{-1}  *  B^{-1} *  C^{-1}

So substituting for D in the above equation

                 (ABC) *  A^{-1}  *  B^{-1} *  C^{-1} =  I

                 I =  I

This proof that  ABC is invertible

 

4 0
3 years ago
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