Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
Answer:
9m +3
Step-by-step explanation:
6m-4+3m+7
Combine like terms
6m+3m -4+7
9m +3
Step-by-step explanation:
wheres the decimal to compare it to
Answer:
Step-by-step explanation:
Each child received two pieces.
So total pieces received by 4 children = 4*2 = 8
Total pieces = 10 + 8 = 18
