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Agata [3.3K]
3 years ago
10

1. Pane Corp. manufactures and sells a nutrition drink for children. It wants to develop a standard cost per gallon. The followi

ng are required for production of one gallon: Ingredient Lime Kool-Drink Sugar Protein Tablets Water Amount per Gallon 24.0 oz. .72 lb. 2 50 oz. Standard Waste 4% 10% 0% 0% Standard Price $0.15 per oz $0.65 per lb $0.40 per tablet $0.01 per oz Compute the standard usage (quantity) and standard cost of the ingredients for one gallon of the nutrition drink.
Business
1 answer:
olga55 [171]3 years ago
4 0

Answer:

Standard cost = $5.57

Explanation:

As per the data given in the question,

Standard cost = Standard usage * standard price

Ingredient   Amount/gallon  st. waste   St. usage            St. price      St. cost

Lime          24.0 Oz                4%       .96X=24.0 Oz=25 Oz    0.15        $3.75     kool-drink

Sugar        .72 lb                     10%     .90X=.72 lb = 0.8 lb     $0.65      $0.52

Protein tablets 2                     0%                2                         $0.40      $0.80

Water        50 Oz                    0%                50 Oz                 $0.01       $0.50

Total                                                                                                         $5.57

Total standard cost = $3.75 + $0.52 + $0.80 + $0.50

= $5.57

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Supplier dependence

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Jack Simpson, contract negotiator for Nebula Airframe Company, is currently involved in bidding on a follow-up government contra
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Answer: 5,882.5‬ hours

Explanation:

Cumulative Labor Hours to be planned for = Cumulative factor * Time of first unit

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Answer:

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Event Type Assets = Liab. + Equity Rev. - Exp. = Net Inc. Cash Flow Type

1.  AE             + -      = NA    + NA      NA   - NA  = NA           -0A

2. CE             +        = +       +  NA     NA   -  NA =  NA          -OA

3. CE             -         = -       +  NA     NA   -  NA =  NA          +OA

4a. AS           +        =  NA   +  +         +     -  NA =  +              +OA

4b. AU          -         =  NA   +  -         NA   -  +   =  -                -OA

5. CE            -         =  -       +  NA     NA   -  NA =  NA          -OA

6a. AS           +        =  NA   +  +         +     -  NA =  +              +OA

6b. AU          -         =  NA   +  -         NA   -  +   =  -                -OA

7. AU            -         =  NA   +  -         NA   -  -   =   -                -OA

8. AU            -         =  NA   +  -         NA   -  -   =   -                -OA

9. AE            +-       =  NA    + NA     NA   - NA  = NA            -OA

10. AU            -       =  NA   +  -         NA   -  -   =   -                -OA

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Answer:

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Price at the end of Year 3 = \textup{1.25}\times\frac{\textup{(1+0.02)}^4}{\textup{0.12-0.02}}

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