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3 years ago

Triangle ABC has a perimeter of 22cm

Mathematics

1 answer:

AleksAgata [21]3 years ago

3 0

ΔABC is not a right angled triangle.

Step-by-step explanation:

Step 1: Given perimeter of ΔABC = 22 cm, AB = 8 cm and BC = 5 cm. Find AC.

Perimeter = AB + BC + AC

⇒ AC = 22 - (8 + 5) = 22 - 13 = 9 cm

Step 2: Find whether the triangle is right angled using Pythagoras Theorem.

AC² = AB² + BC²

⇒ AC² = 9² = 81

⇒ AB² + BC² = 8² + 5² = 64 + 25 = 89

∴ AC² ≠ AB² + BC²

⇒ ΔABC is not a right angled triangle.

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Step-by-step explanation:

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$\frac{3-4}{3-0}=\frac{-1}{3}=-\frac{1}{3}$

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Answer:

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4 years ago

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Pachacha [2.7K]

Answer:

Coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q $(x_2,y_2)$

We will use the formula of midpoint: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We are given midpoint K and $x_1,y_1$ the coordinates of P we need to find $x_2,y_2$ the coordinates of Q.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\$

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$-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16$

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