A regular oval shape, traced by a point moving in a plane so that the sum of its distances from two other points (the foci) is constant, or resulting when a cone is cut by an oblique plane which does not intersect the base.

7 0

4 years ago

Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial: 15ab-9a^

MrMuchimi

Answer:

$- \bigg(3a - \frac{5}{2} b) \bigg)^{2}$

Step-by-step explanation:

$15ab-9a^2-6 \frac{1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\ \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\ \\ = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2 \\ \\ = - \{ - 15ab + (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 \} \\ \\ = - \{ (3a)^2 + \bigg(\frac{5}{2} b \bigg)^2 - 15ab \} \\ \\ = - \bigg(3a - \frac{5}{2} b \bigg)^{2}$

3 0

3 years ago

Other question that I need help on.

hjlf

Option C is your answer. The way it's worded, it first wants you to find the difference (meaning subtract) between 5 and 6/7 and then multiply by the 5.

3 0

4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

VladimirAG [237]

Answer:

a = 5.

Step-by-step explanation:

The graph here is a probability density graph. What will represent $P(X\le a)$ on the graph?

$P(X\le a)$ is the area

between the graph and the x-axis,
to the left of $a$ .

The area under the graph between 0 and 9 is a trapezoid. Consider the trapezoid in three slices from left to right:

A right triangle of area $\displaystyle \frac{1}{2}\times 0.2\times 4 = 0.4$ ,
A rectangle of area $0.2 \times (5 - 4) = 0.2$ , and
Another right triangle of area $\displaystyle \frac{1}{2} \times 0.2 \times (9 - 5) = 0.4$ .

The area of the leftmost triangle plus that of the rectangle is exactly 0.6. In other words, the area to the left of $a = 5$ between the graph and the x-axis is $0.6$ . $P(X \le 5) = 0.6$ . $a = 5$ .

As a side note $a = 5$ shall be the only answer to this question since the area under the graph to the left of $a$ can only increase or stay constant but not decrease as the value of $a$ increases.

3 0

3 years ago