Answer:
The range for Problem 18 is
The range for problem 19 is
Step-by-step explanation:
To find the range you subtract the smallest value from the largest value. In problem 18 the largest value was 17.6 and the smallest was 1.5.
In problem 19 the largest value was 181 and the smallest was 14
Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
Answer:
f(10) = - 26
Step-by-step explanation:
To evaluate f(10), substitute x = 10 into f(x), that is
f(10) = 4 - 3(10) = 4 - 30 = - 26
Answer:
Step-by-step explanation:
m∠1 = 3 times of m∠2
m∠2 = (1/3) times of ∠1
m∠2 = 24°
If its on a graph just look for the spot where the line meets the y and x-axis