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Mnenie [13.5K]
3 years ago
7

S a punishment for something naughty that we did, my little brother and I have to whitewash both sides of a fence. We start at t

he same time, and we each work at a constant rate.
If we each whitewash one side, I'll finish in 2 hours and my brother will finish in 3 hours. But I'm a nice kid, so after I finish my side, I go around to the other side and help my brother finish his side. From the time I start helping him, how many minutes does it take us to finish the job?

Hint(s):

How many sides per hour can I paint? How about my brother? How about both of us together?
Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
Two and a half hours.
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Step-by-step explanation:

\large\underline{\sf{Solution-}}

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On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{1}{( \sqrt{3}  -  \sqrt{2} ) +  \sqrt{5} }  \times \dfrac{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }{( \sqrt{3}  -  \sqrt{2} ) -  \sqrt{5} }

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\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}

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\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{ {( \sqrt{3}  -  \sqrt{2} )}^{2}  -  {( \sqrt{5}) }^{2} }

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\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{5 - 2 \sqrt{6}   - 5}

\rm \:  =  \: \dfrac{ \sqrt{3} -  \sqrt{2}   -  \sqrt{5} }{ - 2 \sqrt{6}}

\rm \:  =  \: \dfrac{ - ( -  \sqrt{3} +  \sqrt{2}  + \sqrt{5}) }{ - 2 \sqrt{6}}

\rm \:  =  \: \dfrac{-  \sqrt{3} +  \sqrt{2}  + \sqrt{5}}{2 \sqrt{6}}

On rationalizing the denominator, we get

\rm \:  =  \: \dfrac{-  \sqrt{3} +  \sqrt{2}  + \sqrt{5}}{2 \sqrt{6}}  \times \dfrac{ \sqrt{6} }{ \sqrt{6} }

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\rm \:  =  \: \dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}

\rm \:  =  \: \dfrac{-  3\sqrt{2} + 2 \sqrt{3}   + \sqrt{30}}{12}

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\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} } =\dfrac{-  \sqrt{3 \times 3 \times 2} +  \sqrt{2 \times 2 \times 3}  + \sqrt{30}}{12}}}

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<h3><u>More Identities to </u><u>know:</u></h3>

\purple{\boxed{\tt{  {(x  -  y)}^{2} =  {x}^{2} - 2xy +  {y}^{2}}}}

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\purple{\boxed{\tt{  {(x - y)}^{3} =  {x}^{3} - 3xy(x  -  y) -  {y}^{3}}}}

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\pink{\boxed{\tt{  {(x + y)}^{2}  -  {(x - y)}^{2} = 4xy}}}

6 0
3 years ago
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