Answer: B
Step-by-step explanation:
P=R-$10MM
P = ($25MM)-$10MM
P = $15MM
For question 6, recall that a sinusoidal function is of the form
A*sin(ω*t + φ)
where A is the amplitude, ω the angular frequency (in units of radians/second), and φ the phase (in radians). The amplitude is the magnitude of the peaks and troughs, the angular frequency inversely proportional to the period (ω = 2*π/T - the 2*π being a normalizing factor), and the phase a value between 0 and 2*π that "shifts" the graph of the function accordingly.
For question 7, you are being asked to find the composite function obtained by applying g to f, which would be 
. The domain would be the values for which this function is defined, which, assuming it to be a subset of the real numbers, would be the interval (-∞, 3] (as the square root of a negative number is an imaginary number.
The slope is
and the y intercept is -1
so the equation is y =
x-1
X+71=108
because they're alternate angles and alternate angles have the same measures
Problem 10
<h3>Answer: 80 degrees</h3>
Work Shown: 80-0 = 80
You subtract the values on the protractor where the two angle arms line up.
============================================
Problem 11
<h3>Answer: 45 degrees</h3>
Work Shown: 45-0 = 45
Same idea as problem 10
============================================
Problem 12
<h3>Answer: 83 degrees</h3>
Work Shown: 128-45 = 83
Same idea as the others. The arm TS isn't fully on 130 degrees, and it's a bit short of it. It looks to be about 128 degrees or so.
============================================
Problem 13
<h3>Answer: 35 degrees</h3>
Explanation: Luis forgot to subtract the value of each arm of the angle. So he should have done 80-45 = 35. The answer would be 80 degrees if arm TQ was at 0 degrees (so 80-0 = 80), but instead TQ is at 45 degrees.
