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Sav [38]
3 years ago
6

Solve the following equation.

Mathematics
2 answers:
Damm [24]3 years ago
8 0
Post the equeation        20chars
miskamm [114]3 years ago
3 0
Can you post the rest of the question please?
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The geometric sequence would be multiplying by 3
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How do you convert 7(x-4)=14 into a word problem
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7(x - 4) = 14 \\ 7x - 21 = 14 \\ 7x = 14 + 21 \\ 7x = 35 \\  \frac{7x}{7}  =  \frac{35}{7}  \\ x = 5

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The course for a boat race starts at point A and proceeds in the direction of S52'E for 1 hour at 8 knots to point B and then in
KATRIN_1 [288]

Answer:

20.823 nautical miles

S20°E

Step-by-step explanation:

I assume you mean ° (degrees), not ' (minutes).  There are 60 minutes in 1 degree.

S52°E means "south, 52° east", or 52° east of south.

S50°W means "south, 50° west", or 50° west of south.

1 knots = 1 nautical mile / hour, so the boat first travels 8 nautical miles from A to B, then 4.5 nautical miles from B to C, then finally back to A.

If we say A is at the origin, then the coordinates of B are:

(8 sin 52°, -8 cos 52°)

And the coordinates of C are:

(8 sin 52° − 4.5 sin 50°, -8 cos 52° − 4.5 cos 50°)

(2.857, -7.818)

So the distance from A to C is:

x = √(2.857² + (-7.818)²)

x ≈ 8.323

And the total distance of the race is:

d = 8 + 4.5 + 8.323

d = 20.823

The compass bearing from A to C is:

θ = atan(2.857 / 7.818)

θ ≈ S20°E

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3 years ago
Jerry uses 15 pieces of origami paper for his 3 projects. If he uses the origami paper at the same rate for his next project, ho
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He will use as much paper that will work

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