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ruslelena [56]
3 years ago
9

It takes 40 min for a bus to cover 36 miles. A car travels 1.4 times faster. When will they meet if they started 36 miles apart

and simultaneously move towards each other?
Mathematics
2 answers:
Orlov [11]3 years ago
6 0

Let's get a big picture view of what we want to find in this problem. It wants to know when the car and the bus meet, given they're traveling towards each other. To get this in terms of numbers, we want to know how much time has passed when <em>the distance between them is 0</em>. Our unknown - what we want to find - is how much time has passed when that happens. There's another way we could look at this, though. The question says that the car and the bus start 36 miles apart - the moment they're 0 miles apart is <em>the same moment they've traveled 36 miles between them</em>.


In other words, adding the distance traveled by the car and the distance traveled by the bus should get us exactly 36 miles. If we call the car's distance d_c and the bus's distance d_b:


d_c+d_b=36


To find the distance each vehicle travels, we can multiply the <em>speed</em> they're traveling at by the <em>amount of time</em> they've been travelling. We'll call the time traveled t, and we'll measure it in minutes. We'll also call the speed of the car s_c and the speed of the bus s_b. This makes their distances


d_b=s_bt \\d_c=s_ct


There's some other key information we can use to help us, though. We know that the car travels 1.4 times as fast as the bus, which means <em>it travels 1.4 times as far in the same time</em>. Mathematically, we can write this


d_c=1.4d_b


This simplifies the equation at the center of our focus, which we can rewrite now as


1.4d_b+d_b=36\\2.4d_b=36\\d_b=15


substituting our earlier formula for d_b:


s_bt=15


since t is what we're looking for, we want to get it by itself, which we can do by dividing both side of the equation by s_b:


t=\frac{15}{s_b}


s_b, the bus's speed in miles per minute, is actually given in the question; it covers 36 miles in 40 minutes, or 36/40 = 9/10 miles per minute, so s_b=\frac{9}{10}.


Plugging that value in, we find


t = 15 \div \frac{9}{10}=15\times\frac{10}{9}  =\frac{50}{3} =16\frac{2}{3}


So, it takes 16 2/3 minutes, or 16 minutes and 40 seconds for the two vehicles to meet.

sveticcg [70]3 years ago
5 0

<u>Bus:</u>

40 min = 36 miles

1 min = 36 ÷ 40 = 0.9 mile


<u>Car:</u>

1 min = 0.9 x 1.4 = 1.26 miles


<u>Total distance covered by both vehicles in 1 min: </u>

1.26 + 0.9 = 2.16 miles


<u>Time needed for both of them to cover 36km:</u>

36 ÷ 2.16 = 16 2/3 min


Answer: They will meet 16 2/3 mins after they have started.

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Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

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liberstina [14]
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OQ is the altitude of the equilateral triangle, so our answer will be the altitude of the adjacent clockwise equilateral triangle.

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m_a_m_a [10]

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Let's verify each option to see which is correct.

<u>Option A</u>

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<u>Option B</u>

Seven added to difference of b minus two.

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<u>Option C</u>

The quotient of seven divided by b minus two.

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<u>Option D</u>

Two subtracted from seven times b

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<u>Option E</u>

The product of seven and the difference of b minus two

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Option E is correct.

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