So,
123/20 is over 1. The denominator is 20, so what I would do is find out how many <em>whole </em>20's would fit in 123.
The result is that 6 20's would fit in 123 with 3 left over.
The answer is six and three-twentieths (6 3/20). It's already in simplest form.
Answer: E) None of the above
Choice A comes close saying that does diverge, which is true. But that doesn't conclusively say if the original integral converges or diverges. We don't have enough info. If 1/sqrt(x) converged, then we could say definitively that the original integral converged as well.
Answer:
h = 3 cm
Step-by-step explanation:
The area (A) of a triangle is calculated as
A = bh ( b is the base and h the height )
Here A = 7 = ← expressed as an improper fraction
and b = 5 = , thus
× × h = , that is
h =
Multiply both sides by 8 to clear the fractions
21h = 63 ( divide both sides by 21 )
h = 3