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klemol [59]
3 years ago
9

Please help me I don’t know how

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

6 5/6

Step-by-step explanation:

8

- 1 1/6

We need to borrow from the 8

We will borrow 1 from the 8 and make it a 7.  The 1 will be written in the form 6/6

7 6/6

- 1 1/6

-----------------

6  5/6

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-28xy - ( - 4yz ) - ( - 4yx ) - 2zy =
ziro4ka [17]

Answer:

-24xy+2yz

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

#

7 0
3 years ago
PLEASE HELP Look at each statement. Does the statement describe a transformation of the graph of f(x) = x that would result in t
Katarina [22]

Answer:

B,A,B

Step-by-step explanation:

6 0
2 years ago
If 2 sides of a triangle measure 6 and 16 find the range for the 3rd side
tangare [24]

Step-by-step explanation:

Range if third side is in between 10-22

Reason:

<em>For </em><em>the </em><em>lowest </em><em>value </em><em>of </em><em>third </em><em>side </em><em>1</em><em>6</em><em>-</em><em>6</em><em>=</em><em> </em><em>1</em><em>0</em><em> </em>

<em>For </em><em>the </em><em>highest</em><em> </em><em>value</em><em> </em><em>if </em><em>third</em><em> </em><em>side </em><em>1</em><em>6</em><em>+</em><em>6</em><em>=</em><em> </em><em>2</em><em>2</em>

<em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em>

8 0
2 years ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
3 years ago
Plz someone answer this I need the answer quick
pogonyaev

Answer:

<h2>290 m^3</h2>

Solution,

volume = (8 \times 5 \times 5) + (5 \times 6 \times 3) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 200 + 90 \\  \:  \:  \:  \:  \:   \:  \:  \:  \:  = 290 \:  {m}^{3}

Hope this helps..

Good luck on your assignment..

7 0
2 years ago
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