Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
Hence, this is the required solution.
Answer:
I think its a,c,d,f, and g
My back put jalapeño from the asofragus or the diameter of
114
Answer: The given logical equivalence is proved below.
Step-by-step explanation: We are given to use truth tables to show the following logical equivalence :
P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)
We know that
two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.
The truth table is as follows :
P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q)∧(∼Q ∨ P)
T T F F T T T T
T F F T F F T F
F T T F F T F F
F F T T T T T T
Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.
Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).
Answer:
The correct answer is: " x > 2 " .
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Step-by-step explanation:
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Given the inequality:
" 6x > 12 " ;
Solve in terms of "x" :
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Divide each side of the inequality by "6" ;
to isolate "x" on one side of the inequation; & to solve in terms of "x" ;
→ " 6x / 6 > 12 / 6 " ;
to get:
→ " x > 2 " .
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Hope this is helpful to you.
Best wishes to you in your academic pursuits
— and within the "Brainly" community!
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