What are the missing numbers?

What is the measure of angle A ?<br> what is the measure of angle B ?

lesya692 [45]

Answer:

$\angle\,A=72^o\\\angle\,B=108^o$

Step-by-step explanation:

Notice that buy construction of a parallelogram,the angles $\angle \,A$ and $\angle \,C$ must equal each other. Then, based on the info given, we can write the following equation:

$3\,y+27^o=5\,y-3^o\\27^o+3^o=5\,y-3\,y\\30^o=2\,y\\y=15^o$

Then, angle $\angle \,A$ = $5\,(15^o)-3^o=72^o$ which is also equal to angle B

and since the addition of all internal angles of the parallelogram must equal $360^o$ , then:

$B+D=360^o-72^o-72^o=216^o$

and therefore, since $\angle \,B$ and $\angle \,D$ must be equal, then:

$\angle\,B=\frac{216^o}{2} =108^o$

8 0

3 years ago

This is 20 points if you don't know the answer please don't put your question down thank you...

MissTica

Answer:

I believe it is C) They both involve writing a rate.

hope this helps

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Part A. Write an equation of a line that is perpendicular to the line y = 2/3x + 5 and passes through the point (4, 0).

fenix001 [56]

Answer:

$y = -\frac{3}{2}x+6$

Step-by-step explanation:

Given:

The given equation of the line $y = \frac{2}{3} x + 5$ that passes through the point (4, 0).

Part A.

The equation of the line.

$y=mx+c$ -----------(1)

Where:

m = Slope of the line

c = y-intercept

The given equation of the line.

$y = \frac{2}{3} x + 5$

Comparing the given equation with equation 1.

The slope of the line is $m=\frac{2}{3}$ and y-intercept $c = 5$

We know that the slope of the perpendicular line is $(-\frac{1}{m})$ .

So the slope of the perpendicular line is $(m=-\frac{1}{\frac{2}{3}}=-\frac{3}{2})$ .

Using point slope formula we write the equation of the perpendicular line that passes through the point (4, 0).

$y-y_{1} = m(x-x_{1}$

Now we substitute the slope of the perpendicular line $m=-\frac{3}{2}$ and $y_{1} = 0, x_{1}=4$ from point (4, 0) in above equation.

$y-0 = -\frac{3}{2}(x-4)$

$y = -\frac{3}{2}x-(-\frac{3}{2}\times 4)$

$y = -\frac{3}{2}x-(-3\times 2)$

$y = -\frac{3}{2}x-(-6)$

$y = -\frac{3}{2}x+6$

Therefore the perpendicular line equation is $y = -\frac{3}{2}x+6$ .

Part B.

1. The slope of the perpendicular line is $m=-\frac{3}{2}$ .

2. The y-intercept of the perpendicular line is 6.

3. The equation of the line $y = -\frac{3}{2}x+6$ is perpendicular to the equation of line $y = \frac{2}{3} x + 5$ .

6 0

3 years ago

Lines l and m are parallel line i is represented by the equation 3x+4y=8 if line m passes through the point (2,-5) which equatio

Rus_ich [418]

Answer:

B

Step-by-step explanation:

because the math

6 0

3 years ago

Find The Domain Find the Value

laila [671]

1a) The domain is a set of all real numbers not equal to 5

1b) The domain is a set of all real numbers not equal to 4

<h3>What is the domain of the function?</h3>

Domain of a function is the set of all possible input values that make the function defined.

1a) We are given the function;

C(x) = -3²/(x - 5)

The domain will be a set of values that makes the denominator not equal to zero. Thus;

The domain is a set of all real numbers not equal to 5

1b) The function is; R(x) = 4x/(3x - 12)

The domain will be a set of values that makes the denominator not equal to zero. Thus;

The domain is a set of all real numbers not equal to 4

2a) Function is;

f(x) = (x + 8)/(2x - 1)

f(2) = (2 + 8)/(2(2) - 1)

f(2) = 10/3

f(0) = (0 + 8)/(2(0) - 1)

f(0) = -8

f(-1/2) = (-1/2 + 8)/(2(-1/2) - 1)

f(-1/2) = -15/4

2b) Function is;

r(t) = (t² + 8)/(t³ - 25t)

r(3) = (3² + 8)/(3³ - 25(3)) = -17/48

r(2) = (2² + 8)/(2³ - 25(2)) = -12/42 = -2/7

r(-1) = ((-1)² + 8)/((-1)³ - 25(-1)) = 9/24 = 3/8

Read more about Domain of function at; brainly.com/question/10197594

#SPJ1

3 0

2 years ago