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Dennis_Churaev [7]
3 years ago
11

Jasmine’s race time was 34.287 minutes.round her race time to the nearest 10th of a minute

Mathematics
2 answers:
amm18123 years ago
7 0
Hi!

34.287 rounded to the nearest tenth is 34.290

This is because 7 is greater than 5, so we would round it to the cloest tenth that is slightly higher than 7. =)
stich3 [128]3 years ago
3 0
34.3 minutes because if a number is higher than 5 it rounds up and in this case since the decimals are 2 tenths 8 hundredths and 7 thousandths. because the hundredths value is a number bigger than 5 you would round it up to 1 tenth making the tenths value 3
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Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same poi
skelet666 [1.2K]

Answer:

Alan: 200 m/min

Brian: 150 m/min

Step-by-step explanation:    

Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.

To find : What are their rates, in meters per minute?

Solution :

Let n represent the number of laps that Alan completes in 9 minutes.

Then n-1 is the number of laps Brian completes.

45 seconds = 3/4 minutes.

The difference in their lap times in minutes per lap is

\frac{9}{(n -1)}-\frac{9}{n} =\frac{3}{4}

Solving the equation we get,

\frac{9n-9n+9}{n(n -1)} =\frac{3}{4}

9\times 4=3\times n(n -1)

36=3\times n(n -1)

n^2-n-12=0

n^2-4n+3n-12=0

n(n-4)+3(n-4)=0

(n-4)(n+3)=0

n=4,-3

Neglecting n=-3

So, n=4

Then Alan's speed in m/min is

S=\frac{D}{T}

S_a=\frac{4\times 450}{9}

S_a=200 m/min

Brian completes 3 laps in that 9-minute time, so his rate is

S_b=\frac{3\times 450}{9}

S_b=150 m/min

Therefore, Alan: 200 m/min

Brian: 150 m/min

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Step-by-step explanation:

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